我试图找出以斜杠(/)和两个斜杠(//)开头的字符串。例如,以下是具有少量字符串的数组: 以下是我正在尝试的代码:
$array = @("/website","//windows_service","/console_app","//windows","///IIS","test")
$arraysplit = $array.split(',');
Foreach ($string in $arraysplit)
{
if ($string.StartsWith("/"))
{
Write-Host "$string has one slash."
}
elseif($string.StartsWith("//"))
{
Write-Host "$string has two slashes."
}
else
{
#I want to exit only when below conditions meet
#1. if string doesnot have any slash or
#2. if string has more than two slashes
Write-Host "$string has more number of slashes or it doesnot have any slash. Exiting"
Exit -1
}
}
我不想写更多if
条件来过滤事物,但这不能按预期工作。我想我应该改变逻辑来达到要求。有人可以建议我(我正在寻找动态方法)
答案 0 :(得分:4)
我会编写一个if-test,匹配任何不使用正则表达式的一个或两个斜杠开头的行。尝试:
$array = @("/website","//windows_service","/console_app","//windows","///IIS","test")
Foreach ($string in $array)
{
if ($string -notmatch '^\/{1,2}[^\/]')
{
Write-Host "$string has more number of slashes or it doesnot have any slash. Exiting"
Exit -1
}
}
答案 1 :(得分:0)
只是反转你的测试,因为如果一个单词以//开头,则以/
开头{
"countries" :
[
{
"id": 2,
"country_code": "MY",
"country_name": "Malaysia",
"phone_code": "+60",
"icon": "no-data"
},
{
"id": 2,
"country_code": "MY",
"country_name": "Malaysia",
"phone_code": "+60",
"icon": "no-data"
}
]
}
答案 2 :(得分:0)
if ($string -match '^/*') { write-host $matches[0].length slashes }
是@wOxxOm发布的答案。感谢。