Question

我在python中有一个列表列表如下：

[['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'],
 ['1490026791.59', '2010113820', 'amazon.com', '208.67.222.222'],
 ['1490026791.57', '2010113820', 'amazon.com', '8.8.4.4'],
 ['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'],
 ['1490026791.37', '150612899', 'google.com', '208.67.220.220'],
 ['1490026791.35', '150612898', 'google.com', '208.67.222.222'],
 ['1490026791.33', '150612899', 'google.com', '8.8.4.4'],
 ['1490019411.19', '150612899', 'google.com', '8.8.8.8'],
 ['1490026791.57', '2017032001', 'intuit.com', '208.67.220.220'],
 ['1490026791.47', '2017032001', 'intuit.com', '208.67.222.222'],
 ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'],
 ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]

第1栏：epoch_time
第2列：serial_number
第3栏：域
第4列：服务器

如何遍历每个域的列表列表，以便如果serial_number等于8.8.8.8的serial_number，则删除列表，以便最终输出如下：

['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'],
['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'],
['1490026791.35', '150612898', 'google.com', '208.67.222.222'],
['1490019411.19', '150612899', 'google.com', '8.8.8.8'],
['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'],
['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]

Answer 1

这应该这样做：

a = [['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'],
 ['1490026791.59', '2010113820', 'amazon.com', '208.67.222.222'],
 ['1490026791.57', '2010113820', 'amazon.com', '8.8.4.4'],
 ['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'],
 ['1490026791.37', '150612899', 'google.com', '208.67.220.220'],
 ['1490026791.35', '150612898', 'google.com', '208.67.222.222'],
 ['1490026791.33', '150612899', 'google.com', '8.8.4.4'],
 ['1490019411.19', '150612899', 'google.com', '8.8.8.8'],
 ['1490026791.57', '2017032001', 'intuit.com', '208.67.220.220'],
 ['1490026791.47', '2017032001', 'intuit.com', '208.67.222.222'],
 ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'],
 ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]

remove = [item[1] for item in a if item[3]=='8.8.8.8']
clean = [item for item in a if item[1] not in remove or item[3]=='8.8.8.8']
print clean

Answer 2

你没有写任何代码，所以我也不会。

创建一组禁止的serial_numbers
在列表中迭代一次。
如果serial_numbers为ip，请将序列号添加到8.8.8.8。
第二次迭代列表，列表理解。
如果ip为8.8.8.8或serial_number不在，则保留元素 serial_numbers。

编写和快速运行将会很短。

Answer 3

我会对列表进行排序，以便在开头显示地址为8.8.8.8的行，然后我会遍历列表，在插入时标记密钥（序列，域），以确保只插入一次。< / p>

l = [['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'],
 ['1490026791.59', '2010113820', 'amazon.com', '208.67.222.222'],
 ['1490026791.57', '2010113820', 'amazon.com', '8.8.4.4'],
 ['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'],
 ['1490026791.37', '150612899', 'google.com', '208.67.220.220'],
 ['1490026791.35', '150612898', 'google.com', '208.67.222.222'],
 ['1490026791.33', '150612899', 'google.com', '8.8.4.4'],
 ['1490019411.19', '150612899', 'google.com', '8.8.8.8'],
 ['1490026791.57', '2017032001', 'intuit.com', '208.67.220.220'],
 ['1490026791.47', '2017032001', 'intuit.com', '208.67.222.222'],
 ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'],
 ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]

inserted = set()
result = []
for row in sorted(l,key=lambda r: r[3]!="8.8.8.8"):
    timestamp,serial,domain,server = row
    k = (serial,domain)
    if k in inserted:
        pass  # already in result: skip
    else:
        result.append(row)
        inserted.add(k)

结果：

[['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'], ['1490019411.19', '150612899', 'google.com', '8.8.8.8'], ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8'], ['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'], ['1490026791.35', '150612898', 'google.com', '208.67.222.222'], ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4']]

Answer 4

您可以获取与服务器关联的所有serial_number（8.8.8.8），然后在使用if条件形成列表时忽略它们！

data=[['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'],
      ['1490026791.59', '2010113820', 'amazon.com', '208.67.222.222'],
      ['1490026791.57', '2010113820', 'amazon.com', '8.8.4.4'],
      ['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'],
      ['1490026791.37', '150612899', 'google.com', '208.67.220.220'],
      ['1490026791.35', '150612898', 'google.com', '208.67.222.222'],
      ['1490026791.33', '150612899', 'google.com', '8.8.4.4'],
      ['1490019411.19', '150612899', 'google.com', '8.8.8.8'],
      ['1490026791.57', '2017032001', 'intuit.com', '208.67.220.220'],
      ['1490026791.47', '2017032001', 'intuit.com', '208.67.222.222'],
      ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'],
      ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]


serv='8.8.8.8'
fil=filter(None,map(lambda x: x[1] if x[3]==serv else None, data))
print [i for i in data if i[1] not in fil or i[3] == serv]

输出：

[['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'], ['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'], ['1490026791.35', '150612898', 'google.com', '208.67.222.222'], ['1490019411.19', '150612899', 'google.com', '8.8.8.8'], ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'], ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]

如果你计算时间，关于使用列表理解（少数其他解决方案），

7.9870223999e-05

使用lambda和map

4.81605529785e-05

在这种情况下这应该是一个问题，但是当数据集很大时，时间确实很重要。希望它有所帮助！

Answer 5

只需创建过滤器列表，然后对列表解析应用过滤：

>>> l = [['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220'],
 ['1490026791.59', '2010113820', 'amazon.com', '208.67.222.222'],
 ['1490026791.57', '2010113820', 'amazon.com', '8.8.4.4'],
 ['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8'],
 ['1490026791.37', '150612899', 'google.com', '208.67.220.220'],
 ['1490026791.35', '150612898', 'google.com', '208.67.222.222'],
 ['1490026791.33', '150612899', 'google.com', '8.8.4.4'],
 ['1490019411.19', '150612899', 'google.com', '8.8.8.8'],
 ['1490026791.57', '2017032001', 'intuit.com', '208.67.220.220'],
 ['1490026791.47', '2017032001', 'intuit.com', '208.67.222.222'],
 ['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4'],
 ['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']]
>>>
>>> ip_check = '8.8.8.8'
>>> filter_serials = [lst[1] for lst in l if lst[3] == ip_check]
>>> filter_serials
['2010113820', '150612899', '2017032001']
>>> 
>>> output_list = [lst for lst in l if lst[3] == ip_check or lst[1] not in filter_serials]
>>> 
>>> for lst in output_list:
    print(lst)


['1490011456.91', '2010113819', 'amazon.com', '208.67.220.220']
['1490026791.55', '2010113820', 'amazon.com', '8.8.8.8']
['1490026791.35', '150612898', 'google.com', '208.67.222.222']
['1490019411.19', '150612899', 'google.com', '8.8.8.8']
['1490026791.45', '2017032000', 'intuit.com', '8.8.4.4']
['1490026791.43', '2017032001', 'intuit.com', '8.8.8.8']

根据条件迭代列表和删除列表的python列表

5 个答案: