Question

我想要做的就是拉出所有拥有12名以上球员的球队。我被告知我需要使用带有计数的.annotate来完成它。我正在查看https://docs.djangoproject.com/en/1.10/topics/db/aggregation/但不明白如何对其进行查询并将其放入html中。我假设拉一个查询，然后做html使它做正确的计数。

指派的问题是......显示所有拥有12名或更多球员的球队，过去和现在。（提示：查看Django注释函数。）

views.py

from django.shortcuts import render, redirect
from .models import League, Team, Player

from . import team_maker

def index(request):
    context = {
        "leagues": League.objects.all(),
        "teams": Team.objects.all(),
        "players": Player.objects.all(),
        "baseball" : League.objects.filter(sport__contains="Baseball"),
        "women" : League.objects.filter(name__contains="Womens'"),
        "ice" : League.objects.filter(sport__contains="ice"),
        "nofootball" : League.objects.exclude(sport__contains="football"),
        "conferences" : League.objects.filter(name__contains="conference"),
        "atlantic": League.objects.filter(name__contains="Atlantic"),
        "teamdallas": Team.objects.filter(location__contains="Dallas"),
        "raptor": Team.objects.filter(team_name__contains="Raptor"),
        "cityloc": Team.objects.filter(location__contains="city"),
        "startT": Team.objects.filter(team_name__startswith="T"),
        "abc": Team.objects.order_by('location'),
        "cba": Team.objects.order_by('location').reverse(),
        "cooper": Player.objects.filter(last_name="Cooper"),
        "joshua": Player.objects.filter(first_name="Joshua"),
        "nocooper": Player.objects.filter(last_name="Cooper").exclude(first_name="Joshua"),
        "wyatt": Player.objects.filter(first_name="Alexander")|Player.objects.filter(first_name="Wyatt"),
        "atlanticsoccer" : Team.objects.filter(league__name__contains='atlantic', league__sport__contains="soccer"),
        "bostonp" : Player.objects.filter(curr_team__team_name__contains='Penguins'),
        "icbc" : Player.objects.filter(curr_team__league__name__contains='International Collegiate Baseball '),
        "footballlopez" : Player.objects.filter(curr_team__league__name__contains="American Conference of Amateur Football", last_name__contains="lopez"),
        "footballplayer" : Player.objects.filter(curr_team__league__sport__contains="football"),
        "sophia" : Team.objects.filter(curr_players__first_name__contains='sophia'),
        "sophiale" :League.objects.filter(teams__curr_players__first_name__contains='sophia'),
      "notrough" :Player.objects.filter(last_name__contains='Flores').exclude(curr_team__team_name__contains='rough'),
      "sevans" :Team.objects.filter(all_players__first_name__contains='Samuel'),
      "Tiger" :Player.objects.filter(all_teams__team_name__contains='Tiger'),
      "vikings":Player.objects.filter(all_teams__team_name__contains='vikings'),
      "jgray":Team.objects.filter(all_players__first_name__contains='Jacob').exclude(team_name__contains='colts'),
      "joshua":Player.objects.filter(all_teams__league__name__contains='Atlantic Federation of Amateur Baseball')&Player.objects.filter(first_name='Joshua'),
      "num12":Player.objects.annotate(num13=)



    }

        return render(request, "leagues/index.html", context)

def make_data(request):
    team_maker.gen_leagues(10)
    team_maker.gen_teams(50)
    team_maker.gen_players(200)

    return redirect("index")

models.py

from django.db import models

class League(models.Model):
    name = models.CharField(max_length=50)
    sport = models.CharField(max_length=15)
    created_at = models.DateTimeField(auto_now_add=True)
    updated_at = models.DateTimeField(auto_now=True)

class Team(models.Model):
    location = models.CharField(max_length=50)
    team_name = models.CharField(max_length=50)
    league = models.ForeignKey(League, related_name="teams")

class Player(models.Model):
    first_name = models.CharField(max_length=15)
    last_name = models.CharField(max_length=15)
    curr_team = models.ForeignKey(Team, related_name="curr_players")
    all_teams = models.ManyToManyField(Team, related_name="all_players")

Answer 1

Team.objects.annotate(c=Count('all_players')).filter(c__gt=12')

这样做会是：

在Team模型/表中的每个记录/行中，它将附加/注释新值。 c一个。{1}}。您可以随意命名。此c将是与此player / row相关联的record的数量。
然后，由于c值在所有行中都有注释，因此它会过滤这些值并获取c大于12（player s）的所有行。< / p>

使用注释django

1 个答案: