Question

我有两张桌子e和o1 表e具有

的位置

Onumber        edt_image
1       AA
1       AB
1       AC
1       AA
1       AB
2       AB
3       AB
3       AA

表o1有

Onumber         Obill      
1                           ABCD
2                           ABCD  
3                            ABCD

所以，当我希望sql拉我Onumber没有AA和obill“ABCD”时，我的意思是

Onumber         edt_image
2       AB

但是现在它拉我了

Onumber Edt_image
1       AB
1       AC
1       AB
2       AB
3       AB

我使用的sql

Select e.onumber,o1.onumber
From e join o1 on o1.onumber=e.onumber
Where e.edt_image<>’AA’
And o1.obill=ABCD

Answer 1

使用EXISTS和NOT EXISTS：

SELECT *
FROM e e1
WHERE NOT EXISTS(SELECT 1 FROM e
                 WHERE Onumber = e1.Onumber
                 AND edt_image = 'AA')
AND EXISTS( SELECT 1 FROM o1
            WHERE Onumber = e1.Onumber
            AND Obill = 'ABCD');

Answer 2

试试这个。希望能帮助到你。

如果您在较大的结果集上运行查询，请考虑在连接键上添加索引。

请注意，请在添加任何索引之前查看对服务器的较大影响

;WITH cte_e (Onumber,edt_image) AS
(
SELECT 1, 'AA' UNION ALL
SELECT 1, 'AB' UNION ALL
SELECT 1, 'AC' UNION ALL
SELECT 1, 'AA' UNION ALL
SELECT 1, 'AB' UNION ALL
SELECT 2, 'AB' UNION ALL
SELECT 3, 'AB' UNION ALL
SELECT 3, 'AA'
), cte_O1(Onumber, Obill)  AS
(
SELECT 1, 'ABCD' UNION ALL
SELECT 2, 'ABCD' UNION ALL 
SELECT 3, 'ABCD'
)
SELECT e1.onumber,
    e1.edt_image
FROM cte_e e1
INNER JOIN cte_O1 o1
    ON o1.Onumber = e1.Onumber
WHERE NOT EXISTS (
        SELECT 1
        FROM cte_e e2
        WHERE e1.Onumber = e2.Onumber
            AND edt_image = 'AA'
        )

即使条件不是拉记录，也要返回记录

2 个答案: