link = http://fortune.com/worlds-most-admired-companies/2016/
所以,我希望div中的所有'href'都具有已知的“类名” 我无法逃脱这个:
import bs4 as bs
import urllib.request
raw = urllib.request.urlopen('http://fortune.com/worlds-most-admired-companies/2016/')
soup = bs.BeautifulSoup(raw, 'lxml')
listdiv = soup.find('div', clsss_="company-franchise-result-content current")
for url in listdiv.find_all('a'):
print(url.get('href'))
我之前使用过:
for a in soup.find_all('a'):
print(a.get('href'))
工作但只返回10项,从苹果到普通电动。甚至当我点击“查看完整列表”按钮时我得到的链接。 我不知道JSON是如何工作的,但它看起来就是这样。
答案 0 :(得分:3)
完整的数据实际上存在于HTML 中。它位于script
标记内的JavaScript对象中。您可以找到此script
标记,获取它的文本,提取JSON字符串,使用json.loads()
将其加载到Python数据结构中并获取所需数据:
In [1]: from bs4 import BeautifulSoup
In [2]: import json
In [3]: import re
In [4]: url = "http://fortune.com/worlds-most-admired-companies/2016/"
In [5]: response = requests.get(url)
In [6]: soup = BeautifulSoup(response.content, "lxml")
In [7]: pattern = re.compile(r"var fortune_wp_vars = ({.*?});", re.DOTALL | re.MULTILINE)
In [8]: script = soup.find("script", text=pattern)
In [9]: data = json.loads(pattern.search(script.get_text()).group(1))
In [10]: companies = data["bootstrap"]["franchise"]["filtered_sorted_data"]
In [11]: for company in companies:
...: print(company["title"])
...:
Apple
Alphabet
...
Yum Brands
ZF Friedrichshafen
Zurich Insurance Group