我已经开始研究使用spring,hibernate,JPA,SOAP webservices的应用程序。现在要求必须在事务中运行某些查询。如果任何一个失败,整个事务应该回滚。
dao层中的代码如下:
import javax.persistence.EntityManager;
import javax.persistence.EntityTransaction;
import javax.persistence.PersistenceContext;
import javax.persistence.PersistenceContextType;
import javax.persistence.Query;
import org.hibernate.Session;
public class BillDAOImpl implements BillDao{
@PersistenceContext(type = PersistenceContextType.EXTENDED)
private EntityManager em;
public boolean processBills() throws Exception{
EntityTransaction tx = null;
Session session = null;
try{
session = em.unwrap(Session.class);
tx = em.getTransaction();
Bill bill = em.find(Bill.class, billId);
//session.beginTransaction();
tx.begin();
...
...
em.persist(bill);
...
...
em.merge(<other object>);
...
...
//session.getTransaction().commit();
tx.commit();
} catch(){
}
}
}
执行tx = em.getTransaction()
时,会出现以下错误:
java.lang.IllegalStateException: Cannot execute getTransaction() on a container-managed EntityManager
其他与交易相关的属性如下:
<bean id="tuneEntityManagerFactory"
class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
p:persistenceXmlLocation="classpath*:META-INF/tune-persistence.xml"
p:persistenceUnitName="tunePersistenceUnit" p:loadTimeWeaver-ref="loadTimeWeaver"
p:jpaVendorAdapter-ref="jpaVendorAdapter" p:jpaDialect-ref="jpaDialect"
p:dataSource-ref="tuneDbDataSource">
<property name="jpaProperties">
<props>
<prop key="hibernate.transaction.manager_lookup_class">org.hibernate.transaction.BTMTransactionManagerLookup
</prop>
<prop key="net.sf.ehcache.configurationResourceName">/${tune-db.ehcache.config.file}</prop>
<prop key="hibernate.transaction.flush_before_completion">false</prop>
<prop key="hibernate.default_schema">${tune-db.schema}</prop>
<prop key="org.hibernate.envers.default_schema">${tune-db.schema}</prop>
<prop key="javax.persistence.validation.mode">${tune-db.data.validation}</prop>
<prop key="hibernate.connection.isolation">3</prop>
<prop key="hibernate.connection.release_mode">auto</prop>
<prop key="hibernate.show_sql">${tune-db.hibernate.show-sql}</prop>
<prop key="hibernate.format_sql">${tune-db.hibernate.format-sql}</prop>
</props>
</property>
</bean>
<bean id="transactionManager" class="org.springframework.orm.jpa.JpaTransactionManager">
<property name="entityManagerFactory" ref="tuneEntityManagerFactory" />
</bean>
当我使用session.beginTransaction()
和session.getTransaction().commit()
时,它可以正常工作。
但是我想用来自entityManager
的交易替换它。那该怎么办?
答案 0 :(得分:3)
尝试注入EntityManagerFactory,然后手动创建EntityManager:
@PersistenceUnit
private EntityManagerFactory entityManagerFactory;
public boolean processBills() throws Exception{
EntityManager em = entityManagerFactory.createEntityManager();
EntityTransaction tx = null;
Session session = null;
try{
session = em.unwrap(Session.class);
tx = em.getTransaction();
答案 1 :(得分:1)
@PersistenceContext返回的EntityManager实例始终是容器管理的EntityManager。容器管理的EntityManager始终是JTA EntityManagers,因此它们的生命周期由容器管理。我想现在有理由说为什么在它们上调用getTransaction()是违法的。This might help
答案 2 :(得分:0)
使用值hibernate.jta.allowTransactionAccess
添加true
属性,您应该可以手动使用它。虽然混合你的策略不是一个好习惯,但是有些代码是由JTA管理的,有些是手动的。
答案 3 :(得分:-1)
@Transactional注释将完全满足您的需求。