Question

以下是XML：

<columninfo name="f1config">
    <column name="col1,col2" fieldname="c1" type="string" />
    <column name="col3" fieldname="c3" type="date" format="ddMMMyyy"/>
    <column name="col4,col5" fieldname="c4" type="string" format="ddMMMyyy"/>
 </columninfo>

如何将上面的反序列化到下面的columninfo类：

public class columninfo
{
 public string name {get;set;}
 public Dictionary<string,column> fieldList {get;set;}
}

public class column
{
  public string name {get;set;}
  public string fieldname {get;set}
  public string format {get;set;}
}

问题在于集合对象 - fieldList。

Answer 1

尝试这样的事情

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;

namespace ConsoleApplication48
{
    class Program
    {
        const string FILENAME = @"c:\temp\test.xml";
        static void Main(string[] args)
        {
            XDocument doc = XDocument.Load(FILENAME);

            columninfo.info = doc.Descendants("columninfo").Select(x => new columninfo() {
                name = (string)x.Attribute("name"),
                fieldList = columninfo.GetDictionary(x)
            }).ToList();

        }
    }
    public class columninfo
    {
        public static List<columninfo> info = new List<columninfo>();
        public string name {get;set;}
        public Dictionary<string,column> fieldList {get;set;}

        public static Dictionary<string,column> GetDictionary(XElement columninfo)
        {
            Dictionary<string,column> dict = new Dictionary<string,column>();

            foreach(XElement column in columninfo.Elements("column"))
            {
                string fieldname = (string)column.Attribute("fieldname");
                string _type = (string)column.Attribute("type");
                string name = (string)column.Attribute("name");

                column newCol;
                string[] names;
                switch(fieldname)
                {
                    case "c1" :
                        names = name.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries);
                        newCol = new column() { name = names[0], format = _type, fieldname = fieldname };
                        dict.Add("c1", newCol);
                        newCol = new column() { name = names[1], format = _type, fieldname = fieldname };
                        dict.Add("c2", newCol);
                        break;

                    case "c3":
                        newCol = new column() { name = fieldname, format = _type, fieldname = fieldname };
                        dict.Add("c3", newCol);
                        break;

                    case "c4":
                        names = name.Split(new char[] { ',' }, StringSplitOptions.RemoveEmptyEntries);
                        newCol = new column() { name = names[0], format = _type, fieldname = fieldname };
                        dict.Add("c4", newCol);
                        newCol = new column() { name = names[1], format = _type, fieldname = fieldname };
                        dict.Add("c5", newCol);
                        break;
                }
            }

            return dict;
        }
    }

    public class column
    {
        public string name { get; set; }
        public string fieldname { get; set; }
        public string format { get; set; }
    }
}

Answer 2

我已进入两个阶段，1）反序列化为包含数组的对象，然后2）然后通过linq转换为字典。

由于

如何将XML反序列化为特定结构（包含集合）

2 个答案: