main.html中
<!DOCTYPE html>
<html>
<head>
<title></title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script src="jquery-3.1.1.min.js"></script>
<script src="jsfile.js"></script>
</head>
<body>
<button onclick="cart(0)"> hi </button>
<p id="disp"></p>
</body>
</html>
jsfile.js
function cart(id1)
{
var id=id1;
//alert("enterd "+id);
document.getElementById("disp").innerHTML ="hi";
if (window.jQuery) {
// jQuery is available.
// Print the jQuery version, e.g. "1.0.0":
//alert(window.jQuery.fn.jquery);
}
$.ajax({
url:"add.php ",
type:"POST",
data:{
item_id: id,
},
success:function(response) {
document.getElementById("disp").innerHTML =response.value1;
},
error:function(){
alert("error");
}
});
}
add.php
<?php
if(isset($_POST['item_id'])){
//if(count($_POST)>0)
echo json_encode(array("value1" => "hello", "value2" => "hi"));
}
?>
收集从add.php到jsfile.js的信息...我无法从json数组中获取信息..我试图通过respnse.value1获取信息。但它返回我未定义..可能是错误??
答案 0 :(得分:0)
在使用之前,您必须解析JSON。将您的成功功能更改为 -
success:function(response) {
var res = JSON.parse(response);
document.getElementById("disp").innerHTML = res.value1;
},