Question

你好我想在这个代码块中给每个食物包装谷歌搜索链接标签。但是不想手动写出所有的href标签，因为我需要做几个与此类似的块，这将非常耗时。有没有办法让php使用像preg_replace这样的东西来做到这一点。

        <?php switch(date(n)) {
    case 1:
        echo "Garlic, Onion";
        break;
    case 2:
        echo "Cabbage, Carrot, Garlic, Leek, Pea, Wheat";
        break;
    case 3:
        echo "Cabbage, Carrot, Chives, Aubergine, Garlic, Leek, Lettuce, Pea, Rhubarb, Spinach, Tomato";
        break;
    case 4:
        echo "Cabbage, Carrot, Chives, Cucumber, Aubergine, Garlic, Leek, Lettuce, Pea, Pumpkin, Rhubarb, Spinach, Tomato, courgette";
        break;
    case 5:
        echo "Asparagus, Broad Beans, Cabbage, Carrot, Chives, Cucumber, Leek, Lettuce, Oregano, Pea, Pumpkin, Rhubarb, Spinach, Tomato, courgette";
        break;
    case 6:
        echo "Asparagus, Broad Beans, Cabbage, Carrot, Cucumber, Kale, Lettuce, Oregano, Pea, Pumpkin, Rhubarb, Sage, Spinach, Tomato, courgette";
        break;
    case 7:
        echo "Asparagus, Broad Beans, Broccoli, Brussel Sprouts, Cabbage, Carrot, Cauliflower, Cucumber, Kale, Oregano, Parsley, Rhubarb, Sage";
        break;
    case 8:
        echo "Asparagus, Broccoli, Brussel Sprouts, Cabbage, Carrot, Cauliflower, Kale, Oregano, Parsley, Sage";
        break;
    case 9:
        echo "Asparagus, Broccoli, Brussel Sprouts, Cabbage, Carrot, Cauliflower, Kale, Oregano, Parsley";
        break;
    case 10:
        echo "Cabbage, Onion, Parsley";
        break;
    case 11:
        echo "Apples, Garlic, Onion";
        break;
    case 12:
        echo "Apples, Garlic, Onion";
        break;
    }?>

例如对于12月，案例12我希望该行：

echo "<a href='http://www.google.co.uk/search?q=Apples'>Apples</a>, <a href='http://www.google.co.uk/search?q=Garlic'>Garlic</a>, <a href='http://www.google.co.uk/search?q=Onion'>Onion</a>";

Answer 1

如果只是没有标点符号的单词，你可以使用一些正则表达式魔术：

function renderGoogleLinks($line) {
    return preg_replace('/([^[:punct:]\s\t\n\r]+)/', '<a href="http://www.google.co.uk/search?q=\\1">\\1</a>', $line);
}

echo renderGoogleLinks("Apples, Garlic, Onion");

Answer 2

以下是使用数组的另一种解决方案：

<?php

$plants = array(
    1  => array('Garlic', 'Onion'),
    2  => array('Cabbage', 'Carrot', 'Garlic', 'Leek', 'Pea', 'Wheat'),
    3  => array('Cabbage', 'Carrot', 'Chives', 'Aubergine', 'Garlic', 'Leek', 'Lettuce', 'Pea', 'Rhubarb', 'Spinach', 'Tomato'),
    4  => array('Cabbage', 'Carrot', 'Chives', 'Cucumber', 'Aubergine', 'Garlic', 'Leek', 'Lettuce', 'Pea', 'Pumpkin', 'Rhubarb', 'Spinach', 'Tomato', 'courgette'),
    5  => array('Asparagus', 'Broad Beans', 'Cabbage', 'Carrot', 'Chives', 'Cucumber', 'Leek', 'Lettuce', 'Oregano', 'Pea', 'Pumpkin', 'Rhubarb', 'Spinach', 'Tomato', 'courgette'),
    6  => array('Asparagus', 'Broad Beans', 'Cabbage', 'Carrot', 'Cucumber', 'Kale', 'Lettuce', 'Oregano', 'Pea', 'Pumpkin', 'Rhubarb', 'Sage', 'Spinach', 'Tomato', 'courgette'),
    7  => array('Asparagus', 'Broad Beans', 'Broccoli', 'Brussel Sprouts', 'Cabbage', 'Carrot', 'Cauliflower', 'Cucumber', 'Kale', 'Oregano', 'Parsley', 'Rhubarb', 'Sage'),
    8  => array('Asparagus', 'Broccoli', 'Brussel Sprouts', 'Cabbage', 'Carrot', 'Cauliflower', 'Kale', 'Oregano', 'Parsley', 'Sage'),
    9  => array('Asparagus', 'Broccoli', 'Brussel Sprouts', 'Cabbage', 'Carrot', 'Cauliflower', 'Kale', 'Oregano', 'Parsley'),
    10 => array('Cabbage', 'Onion', 'Parsley'),
    11 => array('Apples', 'Garlic', 'Onion'),
    12 => array('Apples', 'Garlic', 'Onion'),
);

function googleLink($myarray) {
    $str = '';
    foreach($myarray as $var) {
        $end  = (next($myarray) == true) ? ', ' : '.';
        $str .= '<a href="http://www.google.co.uk/search?q='.$var.'">'.$var.'</a>'.$end;
    }
    return $str;
}

echo googleLink($plants[date(n)]);

?>

Answer 3

首先，更改echo语句以将它们存储在变量中。（并丢失空格）如下：

$food = "Apples,Garlic,Onion";

IDE中的find-replace应该快速排序。然后在切换块之后执行以下操作：

$foods = explode(',', $food);
foreach ($foods as $food) {
    echo '<a href="http://www.google.co.uk/search?q=';
    echo $food;
    echo '">' . $food . '</a>, ';
}

这实际上会留下训练逗号和空格。因此，您可能希望首先在新变量中连接字符串，修剪尾随空格，然后回显它。但这会让你开始。

Answer 4

function renderGoogleLink($searchTerm){
     $anchor_template = '<a href="http://www.google.co.uk/search?q=#TERM#">#TERM#</a>';
     echo preg_replace("#TERM#", $searchTerm, $anchor_template);
}

换行链接圆词php

4 个答案: