这是我在js中的变种
var schemapost = {};
var schemacrumb = {};
var og = {};
var meta = {};
$.get('json', function(resp) {
schemapost = {
"@context":"http://schema.org",
"@type":"Article",
"mainEntityOfPage":permalink,
"headline":title,
"description":description
};
schemacrumb = {
"@context":"http://schema.org",
"@type":"BreadcrumbList",
};
og = {
"fb:app_id":resp.facebook_app_id,
"fb:admins":resp.facebook_id,
};
meta = {
"description":description,
"keywords":post_keyword,
"robots":"noodp"
};
});
所以我收集一个变量中的所有变量
var schema = [schemapost,schemacrumb,og,meta];
我尝试循环该变量而感到困惑
foreach ( a in schema ){
jQuery.ajax({
type: "POST",
url: "/make_schema.php",
data: { data : JSON.stringify(???EACH VARIABLE NAME??),
post_name : slug ,
variablename : ???EACH VARIABLE NAME?? },
});
}
显然很愚蠢,但我试试这个:
var schema = ["schemapost","schemacrumb","og","meta"];
schema.forEach(function(entry) {
jQuery.ajax({
type: "POST",
url: "/kode/post/make_json",
data: {value : JSON.stringify(entry), post_name:slug, variablename:entry},
});
});
并且输出是字符串..不是我想要的可变数组数据, 任何建议如何循环数组变量并获取每个变量名称,以便我可以用于数据:ajax函数中的variablename?
答案 0 :(得分:0)
只需发送您已创建的完整架构数组
var schema = [schemapost,schemacrumb,og,meta];
使用Jquery post方法:
$.ajax({
type: "POST",
url: "/make_schema.php",
data: { data : schema ,
post_name : slug
});
并在后端进程中捕获完整数组作为数组