用r中的数字向量替换数据帧中的NA

时间:2017-03-20 05:18:51

标签: r vector dataframe replace na

我有以下数据框

enter image description here

我想用这个向量替换NA(除了它是我的类数字,但是我把它改成as.character()并且仍然有同样的错误)

L8Replace <- c("0.56","0.57","0.87",0.81")

我试过了

  mydata[is.na(mydata$Freq2),] <- L8replace

但是得到

  Error in as.Date.numeric(value) : 'origin' must be supplied

我理解为什么R很困惑,但我不知道如何解决它

供您使用,这是我通过dput输入数据时得到的结果:

mydata <- structure(list(Freq2 = structure(c(0.42, 0.6, 0.43, NA, NA, NA, 
NA, NA), .Names = c("2015-04-16", "2015-04-21", "2015-04-26", 
"", "", "", "", "")), myDate = structure(c(16541, 16546, 16551, 
16627, 16643, 16659, 16675, 16691), class = "Date"), numDays = structure(c(0, 
5, 10, 86, 102, 118, 134, 150), class = "difftime", units = "days")), .Names =      c("Freq2", 
 "myDate", "numDays"), row.names = c("2015-04-16", "2015-04-21", 
"2015-04-26", "7", "8", "9", "10", "11"), class = "data.frame")

1 个答案:

答案 0 :(得分:0)

我们需要替换特定的列

mydata$Freq2[is.na(mydata$Freq2)] <- L8Replace
mydata
#            Freq2     myDate  numDays
#2015-04-16  0.42 2015-04-16   0 days
#2015-04-21  0.60 2015-04-21   5 days
#2015-04-26  0.43 2015-04-26  10 days
#7           0.56 2015-07-11  86 days
#8           0.57 2015-07-27 102 days
#9           0.87 2015-08-12 118 days
#10          0.81 2015-08-28 134 days
#11          0.00 2015-09-13 150 days

另外,L8Replace&#39;的length应与“Freq2&#39;

中的NA数相匹配”

数据

L8Replace <-  c(0.56, 0.57, 0.87,0.81, 0)