函数有2个参数，但错误表示0

Question

我收到一个错误，说该函数需要2个参数而且没有给出任何参数。我以为我已经在主函数中使用了getBanner函数2参数。

import socket

def getBanner2(ip, port):
    try:
        s = socket.socket()
        s.connect((ip, port))
        banner = s.recv(1024)
        return banner
    except Exception, e:
        print "[!] " + str(e)
        getBanner2()

def main():
    #ip1 = raw_input('Enter IP > ')
    #port = int(raw_input('Enter Port > '))

    ip1 = '10.10.0.115'
    port = 22

    banner1 = getBanner2(ip1, port)

    if banner1:
        print '[+] ' + ip1 + ': ' + banner1

if __name__ == '__main__':
    main()

以下是错误消息......

Traceback (most recent call last):
  File "./getBanner2.py", line 33, in <module>
    main()
  File "./getBanner2.py", line 26, in main
    banner1 = getBanner2(ip1, port)
  File "./getBanner2.py", line 17, in getBanner2
    getBanner2()
TypeError: getBanner2() takes exactly 2 arguments (0 given)

Answer 1

在getBanner2函数中，您再次调用getBanner2()而没有异常块中的参数。

def getBanner2(ip, port):
    try:
        s = socket.socket()
        s.connect((ip, port))
        banner = s.recv(1024)
        return banner
    except Exception, e:
        print "[!] " + str(e)
        getBanner2(ip, port) # changed

仔细分析追溯，大多数情况下，它足以找出问题所在。