Question

问题是在表格中显示数据（tableview）

加载数据。 2行，我可以在表格中单击它们。但为什么他们没有显示我不明白。提前谢谢你

这是我的控制器类。

function clickHandler() {
  $('body').css('background-color', 'red');
}

和Main：

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<input type="button" onclick="clickHandler()" value="Click me!" />

模特人

package sample;

import javafx.collections.FXCollections;
import javafx.collections.ObservableList;
import javafx.fxml.FXML;
import javafx.scene.control.TableColumn;
import javafx.scene.control.TableView;
import javafx.scene.control.cell.PropertyValueFactory;
import sample.model.Person;

import java.util.ArrayList;

public class Controller {

    public ObservableList<Person> observableList;

    @FXML
    private TableView<Person> table = new TableView<>();

    @FXML
    private TableColumn<Person, String> name;
    @FXML
    private TableColumn<Person, String> surname;
    @FXML
    private TableColumn<Person, String> position;
    @FXML
    private TableColumn<Person, String> city;
    @FXML
    private TableColumn<Person, String> street;
    @FXML
    private TableColumn<Person, Integer> homenumber;
    @FXML
    private TableColumn<Person, String> birthday;
    @FXML
    private TableColumn<Person, Integer> salary;

    private Main mainApp;

    public void setMainApp(Main mainApp) {
        this.mainApp = mainApp;

        // Добавление в таблицу данных из наблюдаемого списка
        table.setItems(getObservableList());
    }


    public void initTable(){

        observableList = getObservableList();
        table.setItems(observableList);

        name = new TableColumn<Person,String>("Имя");
        name.setCellValueFactory(new PropertyValueFactory<>("name"));
        surname = new TableColumn<Person,String>("Фамилия");
        surname.setCellValueFactory(new PropertyValueFactory<>("surName"));
        position = new TableColumn<Person,String>("Должность");
        position.setCellValueFactory(new PropertyValueFactory<>("position"));
        city = new TableColumn<Person,String>("Город");
        city.setCellValueFactory(new PropertyValueFactory<>("city"));
        street = new TableColumn<Person,String>("Город");
        street.setCellValueFactory(new PropertyValueFactory<>("street"));
        homenumber = new TableColumn<Person,Integer>("Дом");
        homenumber.setCellValueFactory(new PropertyValueFactory<>("homeNumber"));
        birthday = new TableColumn<Person,String>("День рождения");
        birthday.setCellValueFactory(new PropertyValueFactory<>("birthday"));
        salary = new TableColumn<Person,Integer>("Зарплата");
        salary.setCellValueFactory(new PropertyValueFactory<>("salary"));

//        table.getColumns().setAll(name, surname, position, city, street, homenumber, birthday, salary);
    }

    public ObservableList<Person> getObservableList(){
        ArrayList<Person> people = new ArrayList<>();
        people.add(new Person(1, "33", "33", "33", "33", "33", 6, "33", 7));
        people.add(new Person(2, "33", "33", "33", "33", "33", 6, "33", 7));
        ObservableList<Person> data = FXCollections.observableArrayList(people);

        return data;
    }

}

SCREENSHOT

JavaFX，tableview的数据并没有出现问题

0 个答案: