Question

我想逐行读取文件并测试第二个文件中的行是否存在于$ 3中然后打印$ 0否则打印该行。我的第一个文件包含这样的值：＆＃34; 00 01 03 。。 80 A1 A2 A3 。。 B5＆＃34;

脚本正常工作到80，但当该行成为字符串时，它不起作用。这是代码

while read -r line
do
cat file2.txt | awk '
 BEGIN { FS="." 
test=0
}
('"$line"'==$1) {test=1
result=$0}
END{
if (test==1) { print result}
else { print '"$line"'}
}
'
done < file1.txt'

Answer 1

这不是$sql = "Select * FROM modems"; $query = $db->prepare( $sql ); $query->execute(); $results = $query->fetchAll( PDO::FETCH_ASSOC ); $return = "Select SUM(maddress) FROM modems"; $query = $db->prepare( $return); $query->execute(); ?>  <table class="table"> <caption>Modem Results Page</caption> <tr> <th>Mac Address</th> <th>Modem Model Number</th> <th>Date</th> <th>Reported Problem</th> <th>Good or Bad</th> <th>Initials</th> <th>Times Returned</th> </tr> <input type='button' value='Return to Modems Page' onclick="location.href='modems.php'"><br><br>  <?php foreach( $results as $row){ echo "<tr><td>"; echo $row['maddress']; echo "</td><td>"; echo $row['mmodel']; echo "</td><td>"; echo $row['date']; echo "</td><td>"; echo $row['mproblem']; echo "</td><td>"; echo $row['good_bad']; echo "</td><td>"; echo $row['initials']; echo "</td><td>"; echo $row['SUM(maddress)']; echo "</td>"; echo "</tr>"; } ?> </table>的正确方法。这样做的惯用方法是

awk

请注意，首先提供第二个文件。另外你提到你比较3美元但是代码说的是1美元。

Answer 2

@karakfa
file2的：

00
01
02
A1
A2
B1
B2



file 1
     B2.9.75.lkf
     B1.69.874.cds
     00.364.6478.abc
     A1.635.7452.cds
     01.36.3214.vcd

我想要那样的输出

00.364.6478.abc
01.36.3214.vcd
02.not found
A1.635.7452.cds
A2.not found
B1.69.874.cds
B2.9.75.lkf

它遵循文件2的顺序，如果它不存在则写入未找到

Answer 3

@ M122015：尝试：

awk 'FNR==NR{q=$1;sub(/.*/,"",$1);sub(/^[[:space:]]+/,"");gsub(/ /,".");A[q]=$0;next} ($0 in A){print $0 "." A[$0];next} !($0 in A){print $0".not found."}' FS="."  Input_file1  Input_file2

读取行时的样本输入和预期输出bash：不能将行与不同的值进行比较

3 个答案: