我需要在SQL中使用Pivot获取按列转换的行,但不能通过我的数据透视查询执行此操作。
create table TestTable
(
id int,
colVal int
)
insert into TestTable values(1,1)
insert into TestTable values(1,2)
insert into TestTable values(1,4)
insert into TestTable values(2,1)
insert into TestTable values(2,2)
insert into TestTable values(2,6)
我试图根据下面的查询where子句获取列中colVal的值。
select * from
(
Select ID,colVal
from TestTable
where ID=1
) as PV
pivot
(max(id) for colVal in([1], [2], [3])) piv
对于每个ID,只能有3个colValues,因此我在数据透视中指定了[1],[2],[3]。
I am looking for output like
ID c1 c2 c3
1 1 2 4
任何人都可以帮助我。
答案 0 :(得分:5)
只需使用Row_Number()创建列序列
select id,[1] as c1,[2] as c2,[3] as c3 from
(
Select ID
,col = row_number() over (Partition By ID Order by colVal)
,colVal
from TestTable
where ID=1
) as PV
pivot
(max(colVal) for col in([1], [2], [3])) piv
返回
ID c1 c2 c3
1 1 2 4
编辑 - 动态版
Declare @SQL varchar(max) = Stuff((Select Distinct ',' + QuoteName(concat('C',row_number() over (Partition By ID Order by colVal)))
From TestTable
Order By 1
For XML Path('')
),1,1,'')
Select @SQL = '
Select [id],' + @SQL + '
From (
Select ID
,col = concat(''C'',row_number() over (Partition By ID Order by colVal))
,colVal
from TestTable
where ID=1
) A
Pivot (max(colVal) For [col] in (' + @SQL + ') ) p'
Exec(@SQL);
2008年编辑
Declare @SQL varchar(max) = Stuff((Select Distinct ',' + QuoteName('C'+cast(row_number() over (Partition By ID Order by colVal) as varchar(10)))
From TestTable
Order By 1
For XML Path('')
),1,1,'')
Select @SQL = '
Select [id],' + @SQL + '
From (
Select ID
,col = ''C''+cast(row_number() over (Partition By ID Order by colVal) as varchar(10))
,colVal
from TestTable
where ID=1
) A
Pivot (max(colVal) For [col] in (' + @SQL + ') ) p'
Exec(@SQL);