将长十六进制字符串拆分为列值并转换为十进制

Question

使用如下的数据框，我需要将hex_string列转换为30列，将它们拆分为4个十六进制字符 - 我为此查看了tidyr，但是我不知道得到什么这样做了，但更喜欢基于tidyr的解决方案。这些十六进制字符需要在最终输出表中进一步转换为十进制值。

df <- data.frame(
  id=c(1,2,3,4),
  loc=c("loc1", "loc2", "loc2", "loc3"),
  hex_string = c(
    "0x005000500050005000400040005000500050005000500050005000500050005000500050005000500050005000500050005000500050005000500050",
    "0x004000400040004000400040004000400040004000400040800080008000800080008000800080008000800080008000800080008000800080008000",
    "0x01000100010000f000f000f000f000f000f000f000f000f000f000f000f000f00100010000f000f000f000f000f000f000f000f000f000f000f000f0",
    "0x800080008000800080008000800080008000800080008000800080008000800080008000800080008000800080008000800080008000800080008000"
    )
  )

Answer 1

$OIDs