Question

我在表1中有两个coulms是name和lastname，如果我使用name和lastname搜索全名，那么我有一个搜索输入，那么结果不可用 here is database structure

，输入代码为

<form class="form-inline" action="searchfrnd.php" method="GET">

            <input style="margin-top:20px;" type="search" class="form-control" name="frnd_search" placeholder="Search your Friends">

            </form>

和php代码是

 $frnd_name=$_GET['frnd_search'];

$sql="select name,lastname,username,email from user where name='$frnd_name'   or lastname='$frnd_name'  or username='$frnd_name' ";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "".$row['name']." ".$row['lastname']."<br>"; }}

Answer 1

尝试此查询：

SELECT 
  name, lastname, username, email 
FROM 
  user 
WHERE 
  CONCAT('%',name,'%') LIKE '$frnd_name' OR
  CONCAT('%',lastname,'%') LIKE '$frnd_name' OR
  CONCAT('%',username,'%') LIKE '$frnd_name'

它会在表单输入中查找name，lastname和username。这远非完美，但是你想做它。

请不要忘记代码的安全性，它是不存在的。

Answer 2

$frnd_name = trim(preg_replace( "/[ ]+/", " ", $_GET['frnd_search'] ) );
$arr = explode(" ", $frnd_name, 2);
if(!empty($arr[1]))
    $sql_where = "name LIKE '%".$arr[0]."%' AND lastname LIKE '%".$arr[1]."%'";
else
    $sql_where = "name LIKE '%".$arr[0]."%' OR lastname LIKE '%".$arr[0]."%'";
$sql = "SELECT name,lastname,username,email FROM user WHERE ".$sql_where;
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
echo "".$row['name']." ".$row['lastname']."<br>"; }}

匹配搜索结果两列一个输入

2 个答案: