Question

CREATE OR REPLACE FUNCTION ComputeFreight(subtotal NUMBER)
RETURN NUMBER
IS
freightCharge NUMBER;
BEGIN
    IF subtotal <= 15000 THEN
    freightCharge := (subtotal * .10);
    ELSIF subtotal > 15000 THEN 
    freightCharge := (subtotal * .15);
    RETURN(freightCharge);
    END IF;
END;

DECLARE
  subtotal NUMBER := 15000;
BEGIN
  DBMS_OUTPUT.PUT_LINE( ComputeFreight(subtotal) );
END;

我不知道我的代码有什么问题，但它始终显示此错误：

声明无效

声明无效

ORA-06503：PL / SQL：返回的函数没有值ORA-06512：at   ＆＃34; SQL_JQQXUMCMKFMRHRPZCYFNBEVTN.COMPUTEFREIGHT＆＃34;，第12行ORA-06512：at   第4行ORA-06512：在＆＃34; SYS.DBMS_SQL＆＃34;，第1721行

Answer 1

return语句应该在if-else之外：

CREATE OR REPLACE FUNCTION ComputeFreight(subtotal NUMBER)
RETURN NUMBER
IS
freightCharge NUMBER;
BEGIN
    IF subtotal <= 15000 THEN
        freightCharge := (subtotal * .10);
    ELSIF subtotal > 15000 THEN 
        freightCharge := (subtotal * .15);
    END IF;
    RETURN(freightCharge);    -- here
END;

Answer 2

如果这是IF语句的惯例，那很好（使用GurV建议放置RETURN语句）。但是，如果您在某种生产中实际需要它，您可能希望简化功能并使其更有效。像这样：

CREATE OR REPLACE FUNCTION ComputeFreight(subtotal NUMBER)
RETURN NUMBER
IS
BEGIN
    RETURN subtotal * (CASE WHEN subtotal <= 15000 THEN 0.1 ELSE 0.15 END);
END;

PL SQL（Oracle）错误中的函数

2 个答案: