Question

@python_2_unicode_compatible

class EmployerProfile(AbstractAddress):
    customer = models.OneToOneField(
        CustomerProfile, verbose_name=_('Customer'),
        related_name='employerprofile')

    company_name = models.CharField(_('Company name'),
                                    max_length=50, blank=True, null=True)
    phone = PhoneField(_('Phone'), max_length=50, blank=True, null=True)
    phone_extension = models.CharField(_('Extension'), max_length=10,
                                       blank=True, null=True)
    job_title = models.CharField(_('Job title'), max_length=50, blank=True,
                                 null=True)
    date_hired = models.DateField(_('Date hired'), blank=True, null=True)
    supervisor_name = models.CharField(_('Supervisor name'), max_length=50,

...
                                       blank=True, null=True)
    has_missing_fields = models.BooleanField(_('Has missing informations'),
                                             default=True)
    manual_validation = GenericRelation(ManualFieldValidation)

这是我想要使用元类

修改的函数

def clean_fields(self):
        if income_source != 'Employed':
            to_empty = [
                "company_name",
                "job_title",
                "date_hired",
                "supervisor_name",
                "phone",
                "phone_extension",
                "civic_number",
                "street",
                "address_line_2",
                "city",
                "state",
                "zip_code",
                ...
            ]
            for field_name in to_empty:
                setattr(self, field_name, None)
        super(EmployerProfile, self).save(*args, **kwargs)

任何人都可以告诉我为什么行super(EmployerProfile, self).save(*args, **kwargs)有这种类型的错误？我花了很少时间弄清问题是什么，但没有成功。

Answer 1

由于给出的原因，您收到错误：未在全局或本地范围中定义名称try n = do (x,y) <- calc n return (x+1, y+1) try2 n = (x+1,y+1) where Just (x,y) = calc n calc x | x == 0 = Nothing | otherwise = Just (x+1, 1) main :: IO () main = print $ try 0。不是kwargs。

未定义的名称'arg'

1 个答案: