Question

def Charater(): 
    UpperCount = 0 
    LowerCount = 0
    word = input('Enter a word: ')
    for letter in word:
        if letter == letter.upper 
            UpperCount = UpperCount + 1
            return UpperCount
        else:
            LowerCount = LowerCount + 1
            return LowerCount

print(Charater())

如果这看起来不好，请不要评价我。但我是初学者，我试图让代码计算用户输入的单词中有多少个大写和小写字符。每次我这样做它返回1.（它可能是我的if语句）。有人可以指出问题并告诉我如何解决它。

Answer 1

您可以使用map与str.isupper和str.islower分别查找大写和小写字符的计数：

>>> my_word = "HelLo WorLd"
>>> lower_count = sum(map(str.islower, my_word))
>>> lower_count
6

>>> upper_count = sum(map(str.isupper, my_word))
>>> upper_count
4

Answer 2

作为一个简短的功能

def count_up_and_low(word):
    u = [x for x in word if x.isupper()]
    l = [x for x in word if x.islower()]

    return len(u), len(v)

Answer 3

这应该有效

 def count_by_case(string):
     upper = sum(letter.isupper() for letter in string)
     lower = sum(letter.islower() for letter in string)
     return lower, upper

 string = "MyString"
 lower, upper = count_by_case(string)
 print("{!r} contains {} upper and {} lower case letters".format(string, upper, lower))

Answer 4

使用$post_data and var postdata，生成器理解和嵌套三元组计算一行：

collections.Counter

结果：

import collections

my_word = "HelLo WorLd"
c = collections.Counter("upper" if x.isupper() else "lower" if x.islower() else "" for x in my_word)
print(c)

Answer 5

def up_low(str):
    upper_count=0
    lower_count=0
    for x in str:
        if x.isupper():
            upper_count+=1
        else:
            lower_count+=1
    print(f'number of upper case letter {upper_count}')
    print(f'number of lower case letter {lower_count}')

计算单词中大写和小写字符的数量

5 个答案: