Question

如果我们从EditText收到输入号码。我们如何创建那么多的ProgressBars？例如，如果输入为5. 5，则应创建progressBar小部件。

Answer 1

在 activity_main.xml 中，在scrollView

<ScrollView
    xmlns:android="http://schemas.android.com/apk/res/android"
    xmlns:tools="http://schemas.android.com/tools"
    android:layout_width="match_parent"
    android:layout_height="wrap_content">

    <LinearLayout
        android:id="@+id/activity_main"
        android:layout_width="match_parent"
        android:layout_height="wrap_content"
        android:orientation="vertical"/>
</ScrollView>

在 MainActivity.java 中添加此代码，将progressBar添加到linearLayout

int wantedNumber = 5; //get that number from the editText.
for (int i = 0; i < wantedNumber; i++) {
    ProgressBar bar = new ProgressBar(this);
    bar.setLayoutParams(new LinearLayout.LayoutParams(LinearLayout.LayoutParams.MATCH_PARENT, LinearLayout.LayoutParams.WRAP_CONTENT));
    LinearLayout linearLayout;
    linearLayout.addView(bar);
}

我只提到了重要的部分，如果你遇到任何问题，请告诉我。

Answer 2

//Progress bar array.
final ProgressBar[] bars = new ProgressBar[numTAs+1];

//Create and initialize the Progress Bar array.
for(int i = 0; i < numTAs + 1; i++){
   //ProgressBar bar = new ProgressBar(this);
   int style = android.R.style.Widget_ProgressBar_Horizontal;
   ProgressBar bar = new ProgressBar(this, null, android.R.attr.progressBarStyleHorizontal);
   bars[i] = bar;
}

//Build Adapter
ArrayAdapter<ProgressBar> adapter = new ArrayAdapter<ProgressBar>(this, R.layout.layout, bars ){

            @Override
            public View getView(int position, View convertView, ViewGroup parent){

                return bars[position];
            }
        };

        ListView list = (ListView) findViewById(R.id.listView);
        list.setAdapter(adapter);

    }

我们如何在Android中添加任意数量的ProgressBars？

2 个答案: