Question

我有以下TempTableA

Application     Id       Merchant
--------------------------------
201797838      331543     681

实际上，ID 331543不是商家681的正确ID。

所以我需要找到正确的ID，然后替换现有的Id。

手动我将执行以下操作以找到正确的ID：

首先，我将使用表格SchemeData中的现有Id 331543查询以下列，如下所示

1. SchemeName 
2. TenureInMonths
3. ROI 
4. Approved 
5. IsSubvented

查询：

select SchemeName, TenureInMonths, ROI, Approved, IsSubvented  
from SchemeData 
where ID in (331543)

我将获得以下输出

SchemeName          TenureInMonths  ROI    Approved   IsSubvented
------------------------------------------------------------------
6 Mnths Vanilla        6             18       1          N

要查找正确的ID，我将查询如下：

 select Id 
 from SchemeData
 where SchemeName like '%6 Mnths Vanilla%' 
   and TenureInMonths = 6 
   and ROI = 18 
   and Approved = 1 
   and IsSubvented = 'N' 
   and Merchant = 681 
   and ID_EndDate >= GETDATE()

我将获得相应商家681的以下ID

Id
-------
317122

现在我将用正确的Id替换现有的Id，我的TempTableA将如下所示

Application     Id       Merchant
--------------------------------
201797838      317122      681

您能否帮助您使用SQL查询找到正确的ID，而不是每次都手动执行，因为有很多ID需要替换，并且需要花费大量时间。

Answer 1

我认为这会根据您的规则为您提供最新的商家ID：

select s.*, s2.id as newid
from schemadata s cross apply
     (select top 1 s2.*
      from schemadata sd2
      where s2.SchemeName like '%' + s2.SchemeName + '%' and
            s2.TenureInMonths = s.TenureInMonths
            s2.ROI = s.ROI and
            s2.Approved = s.Approved and
            s2.IsSubvented = s.IsSubvented
            s2.Merchant = s.Merchant 
            s2.ID_EndDate >= GETDATE()
     ) s2;

如果是这样，您可以轻松地将其放入update：

update s
    set id = s2.id
from schemadata s cross apply
     (select top 1 s2.*
      from schemadata sd2
      where s2.SchemeName like '%' + s2.SchemeName + '%' and
            s2.TenureInMonths = s.TenureInMonths
            s2.ROI = s.ROI and
            s2.Approved = s.Approved and
            s2.IsSubvented = s.IsSubvented
            s2.Merchant = s.Merchant 
            s2.ID_EndDate >= GETDATE()
     ) s2;

如何使用SQL Server中的自联接替换表中新列值的现有列值？

1 个答案: