Question

即使我的代码工作也无法登录。就像激活= 1一样，它会登录，否则就不会登录。在我的表中激活的行已设置为1，这意味着它已被激活。但我无法登录。它总是输出激活= 0，这是登录失败！请点击您电子邮件地址上的链接！

public function index()
{
    $Username=$this->input->post("username");
    $Password=$this->input->post("password");

    $this->form_validation->set_rules("username", "username", "trim|required");
    $this->form_validation->set_rules("password", "password", "trim|required");

    $this->db->where('Username', $this->input->post('username'));
    $this->db->where('Password', $this->input->post('password'));       
    $this->db->select('activated');
    $que=$this->db->get('tblaccount');

    if ($this->form_validation->run()==FALSE)
    {
        $this->load->view('login_view');
    }
    else
    {
        $account=$this->account_model->get_user($Username, sha1($Password));
        if (count($account)>0)
        {
            if ($que->row('activated')==1)
            {
                $sess_data=array('login'=>TRUE, 'picture'=>$account[0]->Picture, 'firstname'=>$account[0]->First_Name, 'lastname'=>$account[0]->Last_Name, 'id'=>$account[0]->AID, 'position'=>$account[0]->Position, 'department'=>$account[0]->Department);
                $this->session->set_userdata($sess_data);

                if ($_SESSION['position']=="Professor")
                {
                    echo "<script type='text/javascript'>alert('Welcome to attendance monitoring system, $_SESSION[firstname] $_SESSION[lastname]!');window.location='".base_url("index.php/main")."';</script>";
                }
                else if ($_SESSION['position']=="Department Chair")
                {
                    echo "<script type='text/javascript'>alert('Welcome to attendance monitoring system, $_SESSION[firstname] $_SESSION[lastname]!');window.location='".base_url("index.php/report")."';</script>";
                }
                else if ($_SESSION['position']=="OSA Faculty"||"Guidance Faculty")
                {
                    echo "<script type='text/javascript'>alert('Welcome to attendance monitoring system, $_SESSION[firstname] $_SESSION[lastname]!');window.location='".base_url("index.php/faculty")."';</script>";
                }
            }
            else if ($que->row('activated')==0)
            {
                $this->session->set_flashdata('msg', '<div class="alert alert-danger text-center">Login failed! Please click the link on your email address!</div>');
                redirect('login');
            }
        }
        else
        {
            $this->session->set_flashdata('msg', '<div class="alert alert-danger text-center">Wrong Username or Password!</div>');
            redirect('login');
        }
    }
}

Answer 1

我不明白你代码的一部分。实际上，您首先放置$this->db->where('Password', $this->input->post('password'));，然后放置$account=$this->account_model->get_user($Username, sha1($Password));

您应该更正第一个添加：sha1($this->input->post('password'))，因为我认为实际上您的请求返回一个空行，这就是为什么使用最后一个条件，因为您没有提供其他条件，这是不好的做法PHP。让我知道！

激活帐户后如何登录？

1 个答案: