Question

如果我们有单引号（＆＃39;），则在下面的行中，我们必须将其替换为＆＃39; ||＆＃39;＆＃39;＆＃39;＆＃39;但如果我们有两次单引号（＆＃39;＆＃39;）那么它应该是原样。

我尝试下面的一段代码，但没有给我正确的输出。

代码段：

static String replaceSingleQuoteOnly = "('(?!')'{0})";
String line2 = "Your Form xyz doesn't show the same child''s name as the name in your account with us.";
System.out.println(line2.replaceAll(replaceSingleQuoteOnly, "'||'''"));

上述代码的实际输出：

Your Form xyz doesn'||'''t show the same child''||'''s name as the name in your account with us.

预期结果：

Your Form xyz doesn'||'''t show the same child''s name as the name in your account with us.

正则表达式正在用 child＆＃39; ||＆＃39替换孩子 ;＆＃39;＆＃39; S 即可。的 子＆＃39;＆＃39; S 应保持原样。

Answer 1

您可以使用lookarounds，例如：

String replaceSingleQuoteOnly = "(?<!')'(?!')";
String line2 = "Your Form xyz doesn't show the same child''s name as the name in your account with us.";
System.out.println(line2.replaceAll(replaceSingleQuoteOnly, "'||'''"));

Answer 2

添加否定背后的内容以确保在另一个'之前没有'个字符，并删除额外的捕获组()

所以请使用(?<!')'(?!')

    String replaceSingleQuoteOnly = "(?<!')'(?!')";
    String line2 = "Your Form xyz doesn't show the same child''s name as the name in your account with us.";
    System.out.println(line2.replaceAll(replaceSingleQuoteOnly, "'||'''"));

输出：

Your Form xyz doesn'||'''t show the same child''s name as the name in your account with us.

根据Apostrophe用法，您只需使用(?i)(?<=[a-z])'(?=[a-z])查找字母包围的'

    String replaceSingleQuoteOnly = "(?i)(?<=[a-z])'(?=[a-z])";
    String line2 = "Your Form xyz doesN'T show the same child''s name as the name in your account with us.";
    System.out.println(line2.replaceAll(replaceSingleQuoteOnly, "'||'''"));

正则表达式取代＆＃39; （单引号一次）但不是＆＃39;＆＃39; （单引号两次）与＆＃39; ||＆＃39;＆＃39;＆＃39;

2 个答案: