Question

可以设置PipeTransform多个过滤器吗？

我试试

 posts;
  postss;
    transform(items: any[]): any[] {
             if (items && items.length)
             this.posts = items.filter(it => it.library = it.library.replace("WH","Warehouse"));
             this.postss = items.filter(it => it.collection = it.collection.replace("CL","Central Library"));                                                        

             return this.posts,this.postss;
         }

这不起作用

但

posts; 
transform(items: any[]): any[] {
                 if (items && items.length)
                 this.posts = items.filter(it => it.library = it.library.replace("WH","Warehouse"));
return this.posts;
             }

这有效。

Answer 1

由于您需要更改filter数组中的每个项目，因此无需使用forEach，请改用transform(items: any[]): any[] { if (items && items.length){ items.forEach((it,index,array) => { array[index].library = it.library.replace("WH","Warehouse"); array[index].collection = it.collection.replace("CL","Central Library"); }); } return items ; }并应用更改：

.clear {
    clear: both;
}

Answer 2

return this.posts.concat(this.postss);

来自concat的文档：

concat()方法返回一个新数组，该数组由调用它的数组组成，并与作为参数提供的数组和/或值连接。

可以设置PipeTransform多个过滤器

2 个答案: