下面给出的代码是CS50问题集3的答案。
请看一下功能:init
,
draw
,
move
,
won
并建议我可以做出一些改进。
实际上我得到了一些我不理解的错误。
/**
* fifteen.c
*
* Implements Game of Fifteen (generalized to d x d).
*
* Usage: fifteen d
*
* whereby the board's dimensions are to be d x d,
* where d must be in [DIM_MIN,DIM_MAX]
*
* Note that usleep is obsolete, but it offers more granularity than
* sleep and is simpler to use than nanosleep; `man usleep` for more.
*/
#define _XOPEN_SOURCE 500
#include <cs50.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
// constants
#define DIM_MIN 3
#define DIM_MAX 9
// board
int board[DIM_MAX][DIM_MAX];
// dimensions
int d;
// prototypes
void clear(void);
void greet(void);
void init(void);
void draw(void);
bool move(int tile);
bool won(void);
int main(int argc, string argv[])
{
// ensure proper usage
if (argc != 2)
{
printf("Usage: fifteen d\n");
return 1;
}
// ensure valid dimensions
d = atoi(argv[1]);
if (d < DIM_MIN || d > DIM_MAX)
{
printf("Board must be between %i x %i and %i x %i, inclusive.\n",
DIM_MIN, DIM_MIN, DIM_MAX, DIM_MAX);
return 2;
}
// open log
FILE *file = fopen("log.txt", "w");
if (file == NULL)
{
return 3;
}
// greet user with instructions
greet();
// initialize the board
init();
// accept moves until game is won
while (true)
{
// clear the screen
clear();
// draw the current state of the board
draw();
// log the current state of the board (for testing)
for (int i = 0; i < d; i++)
{
for (int j = 0; j < d; j++)
{
fprintf(file, "%i", board[i][j]);
if (j < d - 1)
{
fprintf(file, "|");
}
}
fprintf(file, "\n");
}
fflush(file);
// check for win
if (won())
{
printf("ftw!\n");
break;
}
// prompt for move
printf("Tile to move: ");
int tile = get_int();
// quit if user inputs 0 (for testing)
if (tile == 0)
{
break;
}
// log move (for testing)
fprintf(file, "%i\n", tile);
fflush(file);
// move if possible, else report illegality
if (!move(tile))
{
printf("\nIllegal move.\n");
usleep(500000);
}
// sleep thread for animation's sake
usleep(500000);
}
// close log
fclose(file);
// success
return 0;
}
/**
* Clears screen using ANSI escape sequences.
*/
void clear(void)
{
printf("\033[2J");
printf("\033[%d;%dH", 0, 0);
}
/**
* Greets player.
*/
void greet(void)
{
clear();
printf("WELCOME TO GAME OF FIFTEEN\n");
usleep(2000000);
}
/**
* Initializes the game's board with tiles numbered 1 through d*d - 1
* (i.e., fills 2D array with values but does not actually print them).
*/
void init(void)
{
int board[4][4];
int d;
do
{
printf("enter the size of the board\n");
scanf("%i",&d);
}while(d <= 4);
printf("enter the values in the grid\n");
for(int i=0;i<d;i++)
{
for(int j=0;j<d;j++)
{
scanf("%i\n",&board[i][j]); // set tile's value
}
}
if(d%2 == 0)
{
int temp;
temp = board[3][1];
board[3][1] = board[3][2];
board[3][2] = temp;
}
}
/**
* Prints the board in its current state.
*/
void draw(void)
{
int d;
for(int i=0;i<d-1;i++)
{
for(int j=0;j<d;j++)
{
printf("%2i",board[i][j]);
}
printf("\n");
}
do
{
for(int j=0;j<d-1;j++)
{
printf("%2i",board[int i][int j]);
}
} while (int i=d-1);
char board[d-1][d-1] = ' ';
printf("%c \n", board[d-1][d-1]);
}
/**
* If tile borders empty space, moves tile and returns true, else
* returns false.
*/
bool move(int tile)
{
int d;
for(int i=0;i<d;i++)
{
for(int j=0;j<d;j++)
{
if(board[i][j] == tile)
{
return board[i][j];
}
}
}
int temp;
temp = board[2][2];
board[2][2] = board[int i][int j];
board[int i][int j] = temp;
}
/**
* Returns true if game is won (i.e., board is in winning configuration),
* else false.
*/
bool won(void)
{
// TODO
for(i=0;i<d;i++)
{
for(j=0;j<d;j++)
{
if(a[i][j] < a[i+1][j+1])
{
return true;
break;
}
else{
return false;
break;
}
}
}
}
我收到此错误,我无法解决。
format指定类型'int'但参数的类型为'dependent type'
答案 0 :(得分:0)
在init()
函数中,您初始化了board[4][4]
,但已经使用了自定义大小的自定义板,您需要使用d来保持索引,而不是使用4或任何其他固定板大小
同样在init()
功能中,您无需手动输入图块的数字。尝试使用变量(整数并将其分配给所需的磁贴,并在将变量分配给下一个磁贴之前递增该变量。
因此,检查d是偶数还是奇数的条件会有变化。
draw()
函数似乎没问题。
move()
函数存在一些问题。 return board[i][j];
无效,因为函数具有返回类型bool。逻辑似乎是不正确的。如果您还没有,请检查演练。
在won()
函数中,不需要在返回后使用break;
语句。另外,如果你仔细检查你在if条件中写入的条件,它不会检查每个变量与同一行中的下一行或下一行中的下一行,但检查每个变量的对角下一个变量,即使它不存在
我建议您重新观看讲座视频,短片和演练,以便更好地了解代码和C语言。