我的第一个查询
SELECT
id,
year_,
month_
FROM
(SELECT
tp.id,
YEAR(FROM_UNIXTIME(tp.visited_date)) as year_,
MONTH(FROM_UNIXTIME(tp.visited_date)) as month_,
@rn := IF(@prev = CONCAT(YEAR(FROM_UNIXTIME(tp.visited_date)),MONTH(FROM_UNIXTIME(tp.visited_date))), @rn + 1, 1) AS rn,
@prev := CONCAT(YEAR(FROM_UNIXTIME(tp.visited_date)),MONTH(FROM_UNIXTIME(tp.visited_date)))
FROM
tr_place tp
JOIN
(SELECT @prev := NULL, @rn := 0) AS vars
ORDER BY
YEAR(FROM_UNIXTIME(tp.visited_date)) DESC,
MONTH(FROM_UNIXTIME(tp.visited_date)) DESC) AS T1
WHERE
rn < 3;
将返回数据集This is the result which I got from the query
其中的子查询
SELECT
tp.id,
YEAR(FROM_UNIXTIME(tp.visited_date)) as year_,
MONTH(FROM_UNIXTIME(tp.visited_date)) as month_,
@rn := IF(@prev = CONCAT(YEAR(FROM_UNIXTIME(tp.visited_date)),MONTH(FROM_UNIXTIME(tp.visited_date))), @rn + 1, 1) AS rn,
@prev := CONCAT(YEAR(FROM_UNIXTIME(tp.visited_date)),MONTH(FROM_UNIXTIME(tp.visited_date)))
FROM
tr_place tp
JOIN
(SELECT @prev := NULL, @rn := 0) AS vars
ORDER BY
YEAR(FROM_UNIXTIME(tp.visited_date)) DESC,
MONTH(FROM_UNIXTIME(tp.visited_date)) DESC;
返回数据The sub query will returns this data
我需要将子查询的最大rn
作为第一个查询中的列。
我怎样才能做到这一点?
答案 0 :(得分:0)
您可能遇到变量分配问题。您不应该在select
中的多个表达式中引用变量。因此,编写第一个查询的正确方法是:
SELECT id, year_, month_
FROM (SELECT tp.id,
YEAR(FROM_UNIXTIME(tp.visited_date)) as year_,
MONTH(FROM_UNIXTIME(tp.visited_date)) as month_,
(@rn := IF (@prev = CONCAT(YEAR(FROM_UNIXTIME(tp.visited_date)), MONTH(FROM_UNIXTIME(tp.visited_date))), @rn,
if(@prev := CONCAT(YEAR(FROM_UNIXTIME(tp.visited_date)), MONTH(FROM_UNIXTIME(tp.visited_date))), 1, 1
)
) as rn
FROM tr_place tp JOIN
(SELECT @prev := NULL, @rn := 0) AS vars
ORDER BY YEAR(FROM_UNIXTIME(tp.visited_date)) DESC,
MONTH(FROM_UNIXTIME(tp.visited_date)) DESC
) t1
WHERE rn < 3;
请注意,变量赋值都在一个表达式中。
这可能会解决您的问题。