这是检查时显示的代码:
<div class="modulecontent-btn"> ==$0
<a href="addmodule.php?course=81318&instance=51828" class="btn btn-edit btn-flat" data-toggle="tooltip" title="" data-original-title="Edit Module">
<img src="images/icons/pencil_100px.png" width="22" height="22">
</a>
</div>
这是我尝试但失败的代码:
driver.FindElement(By.XPath("//img[@src = 'images/icons/pencil_100px.png']")).Click();
driver.FindElement(By.XPath("//a[@class='btn btn-edit btn-flat']")).Click();
driver.FindElement(By.XPath("//button[contains(text(), 'Edit Module')]")).Click();
我错误地输入了任何值吗?此外,我意识到href链接不是一致的链接,因此我无法不断选择它。我想到了点击图片却失败了
答案 0 :(得分:0)
好像你的img xpath有问题;尝试:
public class LoginModel {
Connection connection;
public LoginModel() {
connection = SqliteConnection.Connector();
if(connection == null) {
System.out.println("Connection to DB Failed");
System.exit(1);
}
}
public boolean isDbConnected() {
try {
return !connection.isClosed();
} catch (SQLException ex) {
Logger.getLogger(LoginModel.class.getName()).log(Level.SEVERE, null, ex);
return false;
}
}
public boolean isLogin(String type, String user, String pass) throws SQLException {
PreparedStatement preparedStatement = null;
ResultSet resultSet = null;
String query = "select * from users where type = ? and username = ? and password = ?";
try {
preparedStatement = connection.prepareStatement(query);
preparedStatement.setString(1, type);
preparedStatement.setString(2, user);
preparedStatement.setString(3, pass);
resultSet = preparedStatement.executeQuery();
//if returns result from db
if(resultSet.next()) {
return true;
}
else {
return false;
}
}
catch(Exception e) {
System.out.println(e);
return false;
}
finally {
preparedStatement.close();
resultSet.close();
}
}
}