Question

我正在尝试将表单数据发布到服务My Post Response From Client

它正在使用该方法，但问题在于获取数据。任何人都建议使用一种方法来检索数据。

这是客户端的课程

 - export class TravelRequestDetails
{
  public InitiatorName:string;
  public EmployeeName:string;
  public IntiatedDate:Date;
  public ProjectName:string;
  public PurposeOfTravel:string;
  public TravelFrom:string;
  public TravelTo:string;
  public StartDate:Date;
  public EndDate:Date;
}

这是我在服务方面的课程

[JsonObject(MemberSerialization.OptIn)]
    public class TravelRequest
    {
        [JsonProperty("InitiatorName")]
        public string InitiatorName { get; set; }
        [JsonProperty("EmployeeName")]
        public string EmployeeName { get; set; }
        [JsonProperty("IntiatedDate")]
        public DateTime InitiatedDate { get; set; }
        [JsonProperty("ProjectName")]
        public string ProjectName { get; set; }
        [JsonProperty("TravelFrom")]
        public string TravelFrom { get; set; }
        [JsonProperty("TravelTo")]
        public string TravelTo { get; set; }
        [JsonProperty("StartDate")]
        public Nullable<DateTime> StartDate { get; set; }
        [JsonProperty("EndDate")]
        public Nullable<DateTime> EndDate { get; set; }
        [JsonProperty("PurposeOfTravel")]
        public string PurposeOfTravel { get; set; }


    }

和服务方法

 [Route("api/CreateRequest")]
        [HttpPost]
        public void CreateTravelRequest(TravelRequest travelDetail)
        {

            //travelDetail = Newtonsoft.Json.JsonConvert.DeserializeObject<TravelRequest>(Convert.ToString(travelDetail));
            //// _travelRepository.CreateTravelRequest(travelDetail);
            //return Ok();
        }

我很困惑在方法中放什么？任何帮助

Answer 1

您需要使用JsonResult作为返回类型

         [HttpPost]
        public JsonResult CreateTravelRequest(TravelRequest travelDetail)
        {

          return Json(travelDetail, JsonRequestBehavior.AllowGet);
        }

如何将数据从客户端传递到服务器端

1 个答案: