Question

目标是迭代一个文件，找到前5名球队和球员的进攻篮板。在该文件中包含多个团队所玩的多个游戏。例如，Grizzlies vs Bears将参加比赛，而灰熊队的一名球员可能会在那场比赛中得到3个篮板，然后在灰熊队和鲨鱼队的比赛中输掉几百线，有些人可能会得到5个篮板。它的格式如下：＆＃39; Off Rebound（1）＆＃39; ＆＃39;关闭反弹（2）＆＃39;，＆＃39;关闭反弹（3）＆＃39;等

目标是在遍历整个文件的循环中放置一个循环。我能够发现每场比赛的最多篮板数为10.而不是做一些非常丑陋的事情并且将10个if / else语句放在1-10中，我想添加一些变量（k）1-10以减少它邋's（我想抽出时间说我意识到代码不是很好。我今晚坐下来第一次看它，我对Python很新，我和＃39;当我得到一个功能齐全的代码时，我会尽力修改它。也许这是一个糟糕的方法，但这就是我要做的事情）。不幸的是，我得到了这个非常奇怪的错误，我已经在我的代码下面粘贴了它。

import pandas as pd
import collections as c

fileRead = pd.read_csv('Sample.csv')

eventDescript = fileRead.event_desc.apply(str)
team = fileRead.team_name.apply(str)
player = fileRead.player_name.apply(str)
topTeams = []
topPlayers = []
i = 0

while (i != len(eventDescript)):
   # print eventDescript.where(eventDescript == 'Off Rebound (1)').dropna()
   for k in range(1,11):
       if eventDescript[i] == 'Off Rebound (' + str(k) + ')' and player[i] != 'nan':
           topTeams.append(team[i])
           topPlayers.append(player[i])
           i = i + 1
       else:
           i = i + 1
   i = i + 1

print c.Counter(topTeams).most_common(5)
print c.Counter(topPlayers).most_common(5)

runfile('/Users/air13/Downloads/untitled2.py', wdir='/Users/air13/Downloads')

错误：回溯（最近一次调用最后一次）：

  File "<ipython-input-239-f1cd8a80a240>", line 1, in <module>
    runfile('/Users/air13/Downloads/untitled2.py', wdir='/Users/air13/Downloads')
  File "/Users/air13/anaconda/lib/python2.7/site-packages/spyder/utils/site/sitecustomize.py", line 866, in runfile
    execfile(filename, namespace)
  File "/Users/air13/anaconda/lib/python2.7/site-packages/spyder/utils/site/sitecustomize.py", line 94, in execfile
    builtins.execfile(filename, *where)
  File "/Users/air13/Downloads/untitled2.py", line 24, in <module>
    if eventDescript[i] == 'Off Rebound (' + str(k) + ')' and player[i] != 'nan':
  File "/Users/air13/anaconda/lib/python2.7/site-packages/pandas/core/series.py", line 603, in __getitem__
    result = self.index.get_value(self, key)
  File "/Users/air13/anaconda/lib/python2.7/site-packages/pandas/indexes/base.py", line 2169, in get_value
    tz=getattr(series.dtype, 'tz', None))
  File "pandas/index.pyx", line 98, in pandas.index.IndexEngine.get_value (pandas/index.c:3557)
  File "pandas/index.pyx", line 106, in pandas.index.IndexEngine.get_value (pandas/index.c:3240)
  File "pandas/index.pyx", line 154, in pandas.index.IndexEngine.get_loc (pandas/index.c:4279)
  File "pandas/src/hashtable_class_helper.pxi", line 404, in pandas.hashtable.Int64HashTable.get_item (pandas/hashtable.c:8564)
  File "pandas/src/hashtable_class_helper.pxi", line 410, in pandas.hashtable.Int64HashTable.get_item (pandas/hashtable.c:8508)
KeyError: 128651

Answer 1

该行发生错误： if eventDescript[i] == 'Off Rebound (' + str(k) + ')' and player[i] != 'nan': 这是一个关键错误，因此 eventDescript 或播放器字典中的 i 键没有任何价值。这是因为您在while循环中使用！= 而不是＆lt; ，并且增加 i 三次，以便 i 变得比你字典的长度更长。

以下是我将如何做到这一点：

import pandas as pd
import collections as c

fileRead = pd.read_csv('Sample.csv')

eventDescript = fileRead.event_desc.apply(str)
team = fileRead.team_name.apply(str)
player = fileRead.player_name.apply(str)
topTeams = []
topPlayers = []

for i in range(len(eventDescript)):
    # print eventDescript.where(eventDescript == 'Off Rebound (1)').dropna()
    if player[i] != 'nan':
        k = int(eventDescript[i].replace('Off Rebound (', '').replace(')', ''))
        if 1 <= k <= 10:
            topTeams.append(team[i])
            topPlayers.append(player[i])

print(c.Counter(topTeams).most_common(5))
print(c.Counter(topPlayers).most_common(5))

我建议你尽可能使用for循环，所以这些错误甚至都不会发生。
你不需要第二次循环。
您可以使用i + = 1

奇怪的Python错误可能是由于循环

1 个答案: