Question

顺序任务返回相同的输出，甚至锁定输出。甚至没有clouser变量。例如

List<Task> tasks = new List<Task>();
for (int i = 0; i < 10; i++)
{
    Task t = Task.Factory.StartNew((arg) =>
      {
          int taskid = (int)i;
          IteratingFunction(taskid);
      }, i);
    tasks.Add(t);
}
Task.WaitAll(tasks.ToArray());

方法是

public void IteratingFunction(int s)
{
    lock (Console.Out)
    {
        Console.WriteLine("Running task is: {0}",s);
    }
}

Answer 1

您正在访问修改后的闭包，尝试捕获lambda函数之外的x值：

List<Task> tasks = new List<Task>();
for (int i = 0; i < 10; i++)
{
    // capture taskid here
    int taskid = (int)i;
    Task t = Task.Factory.StartNew((arg) =>
    {
        IteratingFunction(taskid);
    }, i);
    tasks.Add(t);
}
Task.WaitAll(tasks.ToArray());

如何在顺序任务中设置不同的输出

1 个答案: