我正在疯狂地试图找出我的代码发生了什么。
我目前在CS50的pset4中。恢复挑战。
对于那些不知道它是什么的人： 我们给了一个名为card.raw的文件，其中有一些已删除的照片。我们的任务是实现一个程序，可以做一些取证（idyllically）和恢复丢失的照片。
我附上我的代码：
#include <stdio.h>
#include <stdint.h>
int main(int argc, char *argv[])
{
if (argc != 2)
{
fprintf(stderr, "Usage: ./recover file\n");
return 1;
}
//declaring pointer infile and giving the address of argv[1];
char *infile = argv[1];
//Opening file
FILE *raw_data;
raw_data = fopen(infile, "r");
//Checking for NULL error
if(raw_data == NULL)
{
fprintf(stderr, "Could not open file.\n");
return 2;
}
uint8_t buffer[512]; //Delcaring unsigned int variable type. Array of 512 bytes.
int counter = 0; //Declaring counter for counting jpegs files
FILE *outfile; //Setting pointer named outfile for printing here
char filename[8]; //declaring 'filename' variable for storing the file's name
//While we can reads blocks of memory of 512 bytes from raw_data (aka the address from the infile) into buffer:
while (fread(buffer, 512, 1, raw_data))
{
//Condition for tracking the first bytes that form a JPEG file
if(buffer[0] == 0xff &&
buffer[1] == 0xd8 &&
buffer[2] == 0xff &&
(buffer[3] & 0xf0) == 0xe0)
{
if(counter == 0) //If this is the 1st file, then name the file with
//counter value with 3 digits (%03d)
{
sprintf(filename, "%03d.jpg", counter); // And 3 digits (%i3)
outfile = fopen(filename, "w"); //Open file named outfile in write mode
counter++;
}
else //If this is not the first JPG opened, firstly close the
{ // current open file, and then open a new one with the
fclose(outfile); // current counter value and 3 digits for its name
sprintf(filename, "%03d.jpg", counter);
outfile = fopen(filename, "w"); //Open file named 'outfile' in write mode
counter++;
}
}
fwrite(buffer, 1, sizeof(buffer), outfile); /* Write function that takes buffer data (aka the
pointer to the array of elements to be written,
writes 1 byte of elements of the syze buffer (512)
and it writes it to the output, aka 'outfile' */
}
fclose(outfile); //Remember to close the last file once we get out of the while-loop
}
这是一个棘手的部分：
我已经成功恢复了所有问题图片。 但是，如果我多次运行代码，比如说5次，我最终会出现分段错误。
当我运行check50时，我收到以下消息（在一些成功运行和check50 veredict之后，我将附加一个包含分段错误的图像）。 Click here to see the image
我无法得到它。我觉得记忆可能有些麻烦，但我不知道它是什么。
非常感谢您的时间和帮助。 StackOVerFlow总是一个寻求指导的好地方。
修改的
如果在提示分段错误后运行echo $?，则值为139.
Here's the terminal prompt screenshot
修改
正如@Thomas Dickey指出的那样，该程序正在写一个文件，无论是否有一个打开的文件。
我已经更新并修复了一些我的代码以保持清洁，并添加了if条件以便修复它。
以下是解决方案：
#include <stdio.h>
#include <stdint.h>
int main(int argc, char *argv[])
{
if (argc != 2)
{
fprintf(stderr, "Usage: ./recover file\n");
return 1;
}
//declaring pointer infile and giving the address of argv[1];
char *infile = argv[1];
//Opening file
FILE *raw_data;
raw_data = fopen(infile, "r");
//Checking for NULL error
if(raw_data == NULL)
{
fprintf(stderr, "Could not open file.\n");
return 2;
}
uint8_t buffer[512]; //Delcaring unsigned int variable type. Array of 512 bytes.
int counter = 0; //Declaring counter for counting jpegs files
FILE *outfile; //Setting pointer named outfile for printing here
char filename[8]; //declaring 'filename' variable for storing the file's name
//While we can reads blocks of memory of 512 bytes from raw_data (aka the address from the infile) into buffer:
while (fread(buffer, 512, 1, raw_data))
{
//Condition for tracking the first bytes that form a JPEG file
if(buffer[0] == 0xff &&
buffer[1] == 0xd8 &&
buffer[2] == 0xff &&
(buffer[3] & 0xf0) == 0xe0)
{
if(counter != 0)
{
fclose(outfile); //If this is not the first JPG opened, close previous file
}
sprintf(filename, "%03d.jpg", counter); //print stream to 'filename' the value of 'counter' in 3 digits
outfile = fopen(filename, "w"); //Open file named outfile in write mode
counter++; //Add 1 to counter
}
if(counter != 0) //Don't start writing on a file until the first jpeg is found
{
fwrite(buffer, sizeof(buffer), 1, outfile); /* - Write function that takes buffer data
(aka the array of elements to be written) ,
- Write a block of 512 bytes of elements
(aka the size of buffer),
- 1 block of 512 bytes at a time,
- And it writes it to the output, aka 'outfile' */
}
}
fclose(outfile); //Remember to close the last file once we get out of the while-loop
return 0;
}
答案 0 :(得分：2)
如果标题看起来没问题，程序只会打开输出文件，但无论如何写入输出。如果您阅读的文件没有jpeg标题，则会中断。