如何绕过HTTP错误403:使用Python 3禁止使用urllib.request

时间:2017-03-17 16:59:58

标签: python python-3.x urllib http-status-code-403 urllib3

嗨,不是每次都有时候,当我试图访问LSE代码时,我会抛出每个恼人的HTTP错误403:禁止消息。

任何人都知道如何使用标准的python模块来解决这个问题(很遗憾没有美丽的汤)。

Traceback (most recent call last):
  File "/home/ubuntu/workspace/programming_practice/Assessment/Summative/removingThe403Error.py", line 5, in <module>
    webpage = urlopen(req).read().decode('ISO-8859-1')
  File "/usr/lib/python3.4/urllib/request.py", line 161, in urlopen
    return opener.open(url, data, timeout)
  File "/usr/lib/python3.4/urllib/request.py", line 469, in open
    response = meth(req, response)
  File "/usr/lib/python3.4/urllib/request.py", line 579, in http_response
    'http', request, response, code, msg, hdrs)
  File "/usr/lib/python3.4/urllib/request.py", line 507, in error
    return self._call_chain(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 441, in _call_chain
    result = func(*args)
  File "/usr/lib/python3.4/urllib/request.py", line 587, in http_error_default
    raise HTTPError(req.full_url, code, msg, hdrs, fp)
urllib.error.HTTPError: HTTP Error 403: Forbidden


Process exited with code: 1

然而,偶尔会出现这个错误:

var r = window.setInterval(function(){
$.post('/GetMyData/StoreToken')
    .done(function (data) {
        if (data.result == "Success") {
           window.location.href = '/Success';
    }
});
},3000);

链接到所有可以接受的模块列表:https://docs.python.org/3.4/py-modindex.html

非常感谢提前。

2 个答案:

答案 0 :(得分:1)

看来你的利率有限。尝试入睡并重试。例如:

import urllib
import urllib.request
from time import sleep

LSE_URL = "http://www.londonstockexchange.com/exchange/prices-and-markets/stocks/indices/ftse-indices.html"
WAIT_PERIOD = 15

def stock_data_reader():
    stock_data = get_stock_data()
    while True:
        if not stock_data:
            sleep(WAIT_PERIOD) # sleep for a while until next retry
            stock_data = get_stock_data()                
        else:
            break

    print(stock_data) # do something with stock data



def get_stock_data():
    try:
        infile = urllib.request.urlopen(LSE_URL) # Open the URL
    except urllib.error.HTTPError as http_err:
        print("Error: %s" % http_err)
        return None
    else:
        data = infile.read().decode('ISO-8859-1') # Read the content as string decoded with ISO-8859-1
        return data


stock_data_reader()

答案 1 :(得分:0)

这可能是由于 mod_security 。您需要通过将URL作为浏览器打开来欺骗,而不是 python urllib

在这里,我更正了您的代码:

import urllib.request

url = "http://www.londonstockexchange.com/exchange/prices-and-markets/stocks/indices/ftse-indices.html"

# Open the URL as Browser, not as python urllib
page=urllib.request.Request(url,headers={'User-Agent': 'Mozilla/5.0'}) 
infile=urllib.request.urlopen(page).read()
data = infile.decode('ISO-8859-1') # Read the content as string decoded with ISO-8859-1

print(data) # Print the data to the screen

接下来,您可以使用BeautifulSoup来抓取HTML。