Question

我对HTML，PHP或其他编码方式不太满意。我真的不知道如何使这项工作，但我为我的网站提交了一份提交表格。我确实已经更改了电子邮件，但我仍然收到错误：

“域名”目前无法处理此请求。

我也从这里得到了这段代码，现在我不知道该怎么做

这是HTML表格

<div class="container">
<form class="form-horizontal" role="form" method="post" action="share.php">
<div class="form-group">
    <label for="name" class="col-sm-2 control-label">Name</label>
    <div class="col-sm-10">
        <input type="text" class="form-control" id="name" name="name" placeholder="First & Last Name" value="">
    </div>
</div>
<div class="form-group">
    <label for="email" class="col-sm-2 control-label">Email</label>
    <div class="col-sm-10">
        <input type="email" class="form-control" id="email" name="email" placeholder="example@domain.com" value="">
    </div>
</div>

   <div class="form-group">
  <label class="col-md-2 control-label" for="category">Category</label>
  <div class="col-sm-10">
 <select id="category" name="category" class="form-control">
  <option value="">Student</option>
  <option value="">Parent</option>
  <option value="">School</option>
  </select>
  </div>
  </div>


<div class="form-group">
    <label for="message" class="col-sm-2 control-label">Message</label>
    <div class="col-sm-10">
        <textarea class="form-control" rows="4" name="message"></textarea>
    </div>
</div>
<div class="form-group">
    <label for="human" class="col-sm-2 control-label">2 + 3 = ?</label>
    <div class="col-sm-10">
        <input type="text" class="form-control" id="human" name="human" placeholder="Your Answer">
    </div>
</div>
<div class="form-group">
    <div class="col-sm-10 col-sm-offset-2">
        <input id="submit" name="submit" type="submit" value="Send" class="btn btn-primary">
    </div>
</div>
<div class="form-group">
    <div class="col-sm-10 col-sm-offset-2">
        <! Will be used to display an alert to the user>
    </div>
</div>

这是PHP

<?php
if (isset($_POST["submit"])) {
    $name = $_POST['name'];
    $email = $_POST['email'];
    $category = $_POST['category'];
    $message = $_POST['message'];
    $human = intval($_POST['human']);
    $from = 'IKB FORM'; 
    $to = 'EMAIL'; 
    $subject = 'Importante Ka Ba User ';

    $body = "From: $name\n E-Mail: $email\n Message:\n $message";

    // Check if name has been entered
    if (!$_POST['name']) {
        $errName = 'Please enter your name';
    }

    // Check if email has been entered and is valid
    if (!$_POST['email'] || !filter_var($_POST['email'],    FILTER_VALIDATE_EMAIL)) {
        $errEmail = 'Please enter a valid email address';
    }

    if (!$_POST['category'] {
        $errCategory = 'Please enter a valid email address';
    }

    //Check if message has been entered
    if (!$_POST['message']) {
        $errMessage = 'Please enter your message';
    }
    //Check if simple anti-bot test is correct
    if ($human !== 5) {
        $errHuman = 'Your anti-spam is incorrect';
    }

// If there are no errors, send the email
    if (!$errName && !$errEmail && !$errCategory && !$errMessage && !$errHuman) {
       if (mail ($to, $subject, $body, $from)) {
        $result='<div class="alert alert-success">Thank You! I will be in    touch</div>';
}      else {
        $result='<div class="alert alert-danger">Sorry there was an error sending your message. Please try again later</div>';
    }
}
    }
?>

Answer 1

您忘记了以下if语句中的右括号)：

if (!$_POST['category'] {

将其更改为

if (!$_POST['category']) {

如果您将来遇到脚本问题，请确保启用错误报告。这些错误报告将提供有关已发生事件的大量信息，并使调试变得更加容易。 This answer说明了如何启用它。

域目前无法处理此请求

1 个答案: