Question

我有一张表A，如下所示

id| Name|Subject    
--|-----|-------
1 |Mano |Science   
2 |Pavi |Maths    
3 |Mano |Social    
1 |Kalai|Maths  
4 |Kalai|Science

我希望每列都有不同的值。所以我的输出就像

id|Name | Subject    
--|-----|--------
1 |Mano |Science    
2 |Pavi |Maths    
3 |Kalai|Social    
4 |     |

我尝试过使用游标。但我没有得到我需要的东西。有人帮我搞这个

Answer 1

您似乎只想要一个不同值的列表，而不考虑一起出现的内容。这不是SQL，但可以做到：

select row_number() over (order by n.seqnum) as firstcol, n.name, s.subject
from (select name, row_number() over (order by name) as seqnum
      from t
      group by name
     ) n full outer join
     (select subject, row_number() over (order by subject) as seqnum
      from t
      group by subject
     ) s
     on s.seqnum = n.seqnum;

Answer 2

select    *

from     (select  col,val,dense_rank () over (partition by col order by val)  as dr    
          from    mytable unpivot (val for col in (name,subject)) u
          ) pivot (min(val) for col in ('NAME','SUBJECT'))    

order by  dr

+----+-------+---------+
| DR | NAME  | SUBJECT |
+----+-------+---------+
|  1 | Kalai | Maths   |
|  2 | Mano  | Science |
|  3 | Pavi  | Social  |
+----+-------+---------+

获得不同的感应列值

2 个答案: