Question

我正在Jupyter Notebook中使用plotly来制作等值线。我想绘制一个等值线，但它显示我的空输出。我正在使用离线plotly.In html它的genrated图表成功但当我尝试离线时它显示空输出。请告诉我如何解决这个错误。这是我的代码

from plotly.graph_objs import *
from plotly.offline import download_plotlyjs, init_notebook_mode, iplot
from plotly.offline.offline import _plot_html
init_notebook_mode(connected=True) 
for col in state_df.columns:
    state_df[col] = state_df[col].astype(str)
scl = [[0.0, 'rgb(242,240,247)'],[0.2, 'rgb(218,218,235)'],[0.4, 'rgb(188,189,220)'],\
            [0.6, 'rgb(158,154,200)'],[0.8, 'rgb(117,107,177)'],[1.0, 'rgb(84,39,143)']]

state_df['text'] = state_df['StateCode'] + '<br>' +'TotalPlans '+state_df['TotalPlans']
data = [ dict(
        type='choropleth',
        colorscale = scl,
        autocolorscale = False,
        locations = state_df['StateCode'],
        z = state_df['TotalPlans'].astype(float),
        locationmode = 'USA-states',
        text = state_df['text'],
        marker = dict(
            line = dict (
                color = 'rgb(255,255,255)',
                width = 2
            )
        ),
        colorbar = dict(
            title = "Millions USD"
        )
    ) ]
layout = dict(
        title = 'Plan by States',
        geo = dict(
            scope='usa',
            projection=dict( type='albers usa' ),
            showlakes = True,
            lakecolor = 'rgb(255, 255, 255)',
        ),
    )

fig = dict(data=data, layout=layout)
plotly.offline.iplot(fig)

Answer 1

您正在向dict传递iplot，这与文档相反，只能处理Figure个对象而不是字典。

尝试

fig = Figure(data=[data], layout=layout)

它应该有用。

Jupyter Notebook没有使用plotly绘制输出

1 个答案: