在Scala Spark中,我可以轻松地将列添加到现有的Dataframe书写
val newDf = df.withColumn("date_min", anotherDf("date_min"))
在PySpark中执行此操作会产生AnalysisException
。
以下是我正在做的事情:
minDf.show(5)
maxDf.show(5)
+--------------------+
| date_min|
+--------------------+
|2016-11-01 10:50:...|
|2016-11-01 11:46:...|
|2016-11-01 19:23:...|
|2016-11-01 17:01:...|
|2016-11-01 09:00:...|
+--------------------+
only showing top 5 rows
+--------------------+
| date_max|
+--------------------+
|2016-11-01 10:50:...|
|2016-11-01 11:46:...|
|2016-11-01 19:23:...|
|2016-11-01 17:01:...|
|2016-11-01 09:00:...|
+--------------------+
only showing top 5 rows
然后,导致错误的原因是:
newDf = minDf.withColumn("date_max", maxDf["date_max"])
AnalysisExceptionTraceback (most recent call last)
<ipython-input-13-7e19c841fa51> in <module>()
2 maxDf.show(5)
3
----> 4 newDf = minDf.withColumn("date_max", maxDf["date_max"])
/opt/spark-2.1.0-bin-hadoop2.7/python/pyspark/sql/dataframe.pyc in withColumn(self, colName, col)
1491 """
1492 assert isinstance(col, Column), "col should be Column"
-> 1493 return DataFrame(self._jdf.withColumn(colName, col._jc), self.sql_ctx)
1494
1495 @ignore_unicode_prefix
/opt/spark-2.1.0-bin-hadoop2.7/python/lib/py4j-0.10.4-src.zip/py4j/java_gateway.py in __call__(self, *args)
1131 answer = self.gateway_client.send_command(command)
1132 return_value = get_return_value(
-> 1133 answer, self.gateway_client, self.target_id, self.name)
1134
1135 for temp_arg in temp_args:
/opt/spark-2.1.0-bin-hadoop2.7/python/pyspark/sql/utils.pyc in deco(*a, **kw)
67 e.java_exception.getStackTrace()))
68 if s.startswith('org.apache.spark.sql.AnalysisException: '):
---> 69 raise AnalysisException(s.split(': ', 1)[1], stackTrace)
70 if s.startswith('org.apache.spark.sql.catalyst.analysis'):
71 raise AnalysisException(s.split(': ', 1)[1], stackTrace)
AnalysisException: u'resolved attribute(s) date_max#67 missing from date_min#66 in operator !Project [date_min#66, date_max#67 AS date_max#106];;\n!Project [date_min#66, date_max#67 AS date_max#106]\n+- Project [date_min#66]\n +- Project [cast((cast(date_min#6L as double) / cast(1000 as double)) as timestamp) AS date_min#66, cast((cast(date_max#7L as double) / cast(1000 as double)) as timestamp) AS date_max#67]\n +- SubqueryAlias df, `df`\n +- LogicalRDD [idvisiteur#5, date_min#6L, date_max#7L, sales_sum#8, sales_count#9L]\n'
答案 0 :(得分:3)
希望这有帮助!
import pyspark.sql.functions as f
minDf = sc.parallelize([['2016-11-01 10:50:00'],['2016-11-01 11:46:00']]).toDF(["date_min"])
maxDf = sc.parallelize([['2016-11-01 10:50:00'],['2016-11-01 11:46:00']]).toDF(["date_max"])
# since there is no common column between these two dataframes add row_index so that it can be joined
minDf=minDf.withColumn('row_index', f.monotonically_increasing_id())
maxDf=maxDf.withColumn('row_index', f.monotonically_increasing_id())
minDf = minDf.join(maxDf, on=["row_index"]).sort("row_index").drop("row_index")
minDf.show()
输出是:
+-------------------+-------------------+
| date_min| date_max|
+-------------------+-------------------+
|2016-11-01 10:50:00|2016-11-01 10:50:00|
|2016-11-01 11:46:00|2016-11-01 11:46:00|
+-------------------+-------------------+
答案 1 :(得分:1)
简短的回答是Spark DataFrame API不支持这一点,至少在Spark 2.x中不支持。但是,您可以编写辅助函数来实现类似的功能。
首先让我们创建一些测试数据:
minDf = sc.parallelize(['2016-11-01','2016-11-02','2016-11-03']).map(lambda x: (x, )).toDF(['date_min'])
maxDf = sc.parallelize(['2016-12-01','2016-12-02','2016-12-03']).map(lambda x: (x, )).toDF(['date_max'])
然后,您可以使用zip
组合两个数据帧,前提是数据帧的分区相同:
from pyspark.sql.types import StructType
def zip_df(l, r):
return l.rdd.zip(r.rdd).map(lambda x: (x[0][0],x[1][0])).toDF(StructType([l.schema[0],r.schema[0]]))
combined = zip_df(minDf, maxDf.select('date_max'))
combined.show()
答案 2 :(得分:0)
您可以为两个数据帧创建索引,然后加入它们;像这样:
from pyspark.sql.window import Window
from pyspark.sql.functions import monotonically_increasing_id, row_number
w = Window.orderBy(monotonically_increasing_id())
minDf= minDf.withColumn("columnindex", row_number().over(w))
maxDf= maxDf.withColumn("columnindex", row_number().over(w))
minDf= minDf.join(maxDf, df1_in_indexed.columnindex == maxDf.columnindex, 'inner').drop(maxDf.columnindex)