Question

我有一个sql查询，结果如下表所示。

+-------+----------+---------------------+--------------------------------------+
| tp_id | tp_title | tp_completed_at     | uto_order                            |
+-------+----------+---------------------+--------------------------------------+
| 69033 | task3    | 2017-03-17 08:15:38 | 3401893506280706400000000.0000000000 |
| 69022 | post 1   | 2017-03-15 10:24:03 | 1122274146401882300000000.0000000000 |
| 69032 | task4    | 2017-03-17 08:15:35 |  810531327956915000000000.0000000000 |
| 68998 | final    | 2017-03-13 14:23:18 |  498788509511947700000000.0000000000 |
| 68978 | app4     | 2017-03-13 14:05:39 |  221683782005310100000000.0000000000 |
| 68850 | 7        | 2017-02-24 07:58:38 |   12974633789062503000000.0000000000 |
| 68845 | 6        | 2017-02-24 07:54:14 |    5766503906250001000000.0000000000 |
+-------+----------+---------------------+--------------------------------------+

我想单独根据tp_completed_at和uto_order对结果进行排序。我的意思是，首先查询应该基于tp_completed_at对结果进行排序，然后再次根据uto_order对tp_completed_at中具有相同日期的记录（不包括时间戳）对整个数据进行排序，例如，任务3和任务4在基于tp_completed_at进行排序后将彼此相邻，如下所示

+-------+----------+---------------------+--------------------------------------+
| tp_id | tp_title | tp_completed_at     | uto_order                            |
+-------+----------+---------------------+--------------------------------------+
| 68845 | 6        | 2017-02-24 07:54:14 |    5766503906250001000000.0000000000 |
| 68850 | 7        | 2017-02-24 07:58:38 |   12974633789062503000000.0000000000 |
| 68978 | app4     | 2017-03-13 14:05:39 |  221683782005310100000000.0000000000 |
| 68998 | final    | 2017-03-13 14:23:18 |  498788509511947700000000.0000000000 |
| 69022 | post 1   | 2017-03-15 10:24:03 | 1122274146401882300000000.0000000000 |
| 69032 | task4    | 2017-03-17 08:15:35 |  810531327956915000000000.0000000000 |
| 69033 | task3    | 2017-03-17 08:15:38 | 3401893506280706400000000.0000000000 |
+-------+----------+---------------------+--------------------------------------+

我想再次基于uto_order，（任务4和任务3）基于uto_order，（app4和final）排序（6和7），因为所有这组任务都基于uto_order同一天tp_completed_at。怎么做？在此先感谢!!!

Answer 1

使用：

ORDER BY CAST(tp_completed_at AS DATE) DESC, uto_order

Answer 2

如果您要对date的{{1}}部分进行排序，然后按tp_completed_at进行排序，则可以使用MySQL的uto_order函数，例如：

DATE_FORMAT

基于两列的MySQL排序

2 个答案: