我的问题是我无法从下面的C代码获得AES 256 CTR输出以匹配下面OpenSSL命令的输出。
C代码产生了这个：
5f b7 18 d1 28 62 7f 50 35 ba e9 67 a7 17 ab 22
f9 e4 09 ce 23 26 7b 93 82 02 d3 87 eb 01 26 ac
96 2c 01 8c c8 af f3 de a4 18 7f 29 46 00 2e 00
OpenSSL命令行生成：
5f b7 18 d1 28 62 7f 50 35 ba e9 67 a7 17 ab 22
3c 01 11 bd 39 14 74 76 31 57 a6 53 f9 00 09 b4
6f a9 49 bc 6d 00 77 24 2d ef b9 c4
注意前16个字节是相同的，因为nonceIV是相同的，但是，当nonceIV在下一次迭代时更新，然后与明文进行异或，接下来的16个字节不同，等等......？
我无法理解为什么会这样？任何人都知道为什么十六进制代码在第一个16字节块之后是不同的？
免责声明：我不是C专家。
谢谢！
Fox.txt
The quick brown fox jumped over the lazy dog
然后运行以下OpenSSL命令来创建foxy.exe
openssl enc -aes-256-ctr -in fox.txt -out foxy.exe -K 603deb1015ca71be2b73aef0857d77811f352c073b6108d72d9810a30914dff4 -iv f0f1f2f3f4f5f6f7f8f9fafbfcfdfeff -nosalt -nopad -p
以下是 foxy.exe 包含的内容：
5f b7 18 d1 28 62 7f 50 35 ba e9 67 a7 17 ab 22
3c 01 11 bd 39 14 74 76 31 57 a6 53 f9 00 09 b4
6f a9 49 bc 6d 00 77 24 2d ef b9 c4
这是代码。
#include <Windows.h>
// What is AES CTR
//
// AES - CTR (counter) mode is another popular symmetric encryption algorithm.
//
// It is advantageous because of a few features :
// 1. The data size does not have to be multiple of 16 bytes.
// 2. The encryption or decryption for all blocks of the data can happen in parallel, allowing faster implementation.
// 3. Encryption and decryption use identical implementation.
//
// Very important note : choice of initial counter is critical to the security of CTR mode.
// The requirement is that the same counter and AES key combination can never to used to encrypt more than more one 16 - byte block.
// Notes
// -----
// * CTR mode does not require padding to block boundaries.
//
// * The IV size of AES is 16 bytes.
//
// * CTR mode doesn't need separate encrypt and decrypt method. Encryption key can be set once.
//
// * AES is a block cipher : it takes as input a 16 byte plaintext block,
// a secret key (16, 24 or 32 bytes) and outputs another 16 byte ciphertext block.
//
// References
// ----------
// https://en.wikipedia.org/wiki/Block_cipher_mode_of_operation#Counter_.28CTR.29
// https://www.cryptopp.com/wiki/CTR_Mode#Counter_Increment
// https://modexp.wordpress.com/2016/03/10/windows-ctr-mode-with-crypto-api/
// https://msdn.microsoft.com/en-us/library/windows/desktop/jj650836(v=vs.85).aspx
// http://www.cryptogrium.com/aes-ctr.html
// http://www.bierkandt.org/encryption/symmetric_encryption.php
#define IV_SIZE 16
#define AES_BLOCK_SIZE 16
typedef struct _key_hdr_t {
PUBLICKEYSTRUC hdr; // Indicates the type of BLOB and the algorithm that the key uses.
DWORD len; // The size, in bytes, of the key material.
char key[32]; // The key material.
} key_hdr;
// NIST specifies two types of counters.
//
// First is a counter which is made up of a nonce and counter.
// The nonce is random, and the remaining bytes are counter bytes (which are incremented).
// For example, a 16 byte block cipher might use the high 8 bytes as a nonce, and the low 8 bytes as a counter.
//
// Second is a counter block, where all bytes are counter bytes and can be incremented as carries are generated.
// For example, in a 16 byte block cipher, all 16 bytes are counter bytes.
//
// This uses the second method, which means the entire byte block is treated as counter bytes.
void IncrementCounterByOne(char *inout)
{
int i;
for (i = 16 - 1; i >= 0; i--) {
inout[i]++;
if (inout[i]) {
break;
}
}
}
void XOR(char *plaintext, char *ciphertext, int plaintext_len)
{
int i;
for (i = 0; i < plaintext_len; i++)
{
plaintext[i] ^= ciphertext[i];
}
}
unsigned int GetAlgorithmIdentifier(unsigned int aeskeylenbits)
{
switch (aeskeylenbits)
{
case 128:
return CALG_AES_128;
case 192:
return CALG_AES_192;
case 256:
return CALG_AES_256;
default:
return 0;
}
}
unsigned int GetKeyLengthBytes(unsigned int aeskeylenbits)
{
return aeskeylenbits / 8;
}
void SetKeyData(key_hdr *key, unsigned int aeskeylenbits, char *pKey)
{
key->hdr.bType = PLAINTEXTKEYBLOB;
key->hdr.bVersion = CUR_BLOB_VERSION;
key->hdr.reserved = 0;
key->hdr.aiKeyAlg = GetAlgorithmIdentifier(aeskeylenbits);
key->len = GetKeyLengthBytes(aeskeylenbits);
memmove(key->key, pKey, key->len);
}
// point = pointer to the start of the plaintext, extent is the size (44 bytes)
void __stdcall AESCTR(char *point, int extent, char *pKey, char *pIV, unsigned int aeskeylenbits, char *bufOut)
{
HCRYPTPROV hProv;
HCRYPTKEY hSession;
key_hdr key;
DWORD IV_len;
div_t aesblocks;
char nonceIV[64];
char tIV[64];
char *bufIn;
bufIn = point;
memmove(nonceIV, pIV, IV_SIZE);
SetKeyData(&key, aeskeylenbits, pKey);
CryptAcquireContext(&hProv, NULL, NULL, PROV_RSA_AES, CRYPT_VERIFYCONTEXT | CRYPT_SILENT);
CryptImportKey(hProv, (PBYTE)&key, sizeof(key), 0, CRYPT_NO_SALT, &hSession);
aesblocks = div(extent, AES_BLOCK_SIZE);
while (aesblocks.quot != 0)
{
IV_len = IV_SIZE;
memmove(tIV, nonceIV, IV_SIZE);
CryptEncrypt(hSession, 0, FALSE, 0, (BYTE *)tIV, &IV_len, sizeof(tIV));
XOR(bufIn, tIV, AES_BLOCK_SIZE);
IncrementCounterByOne(nonceIV);
bufIn += AES_BLOCK_SIZE;
aesblocks.quot--;
}
if (aesblocks.rem != 0)
{
memmove(tIV, nonceIV, IV_SIZE);
CryptEncrypt(hSession, 0, TRUE, 0, (BYTE *)tIV, &IV_len, sizeof(tIV));
XOR(bufIn, tIV, aesblocks.rem);
}
memmove(bufOut, point, extent);
CryptDestroyKey(hSession);
CryptReleaseContext(hProv, 0);
}
我能够通过M $ CryptEncrypt（）备注部分https://msdn.microsoft.com/en-us/library/windows/desktop/aa379924(v=vs.85).aspx上建议的伪代码来实现这一点：
// Set the IV for the original key. Do not use the original key for
// encryption or decryption after doing this because the key's
// feedback register will get modified and you cannot change it.
CryptSetKeyParam(hOriginalKey, KP_IV, newIV)
while(block = NextBlock())
{
// Create a duplicate of the original key. This causes the
// original key's IV to be copied into the duplicate key's
// feedback register.
hDuplicateKey = CryptDuplicateKey(hOriginalKey)
// Encrypt the block with the duplicate key.
CryptEncrypt(hDuplicateKey, block)
// Destroy the duplicate key. Its feedback register has been
// modified by the CryptEncrypt function, so it cannot be used
// again. It will be re-duplicated in the next iteration of the
// loop.
CryptDestroyKey(hDuplicateKey)
}
以下是添加了两个新行的更新代码：
HCRYPTKEY hDuplicateKey;
boolean final;
while (aesblocks.quot != 0)
{
CryptDuplicateKey(hOriginalKey, NULL, 0, &hDuplicateKey);
IV_len = IV_SIZE;
memmove(tIV, nonceIV, IV_len);
final = (aesblocks.quot == 1 && aesblocks.rem == 0) ? TRUE : FALSE;
CryptEncrypt(hDuplicateKey, 0, final, 0, (BYTE *)tIV, &IV_len, sizeof(tIV));
XOR(bufIn, tIV, AES_BLOCK_SIZE);
IncrementCounterByOne(nonceIV);
bufIn += AES_BLOCK_SIZE;
aesblocks.quot--;
CryptDestroyKey(hDuplicateKey);
}
if (aesblocks.rem != 0)
{
CryptDuplicateKey(hOriginalKey, NULL, 0, &hDuplicateKey);
final = TRUE;
memmove(tIV, nonceIV, IV_SIZE);
CryptEncrypt(hDuplicateKey, 0, final, 0, (BYTE *)tIV, &IV_len, sizeof(tIV));
XOR(bufIn, tIV, aesblocks.rem);
CryptDestroyKey(hDuplicateKey);
}
答案 0 :(得分：2)
我不熟悉Microsoft API，但我相信CryptEncrypt（）默认使用CBC模式 - 因此第一个加密块的输出会自动输入第二个块的输入。你自己从头开始建立点击率模式（顺便提一下通常不是一件明智的事情 - 你应该使用加密库的功能而不是“自己动手”加密）。要获得预期的输出，您可能需要让CryptEncrypt在ECB模式下使用AES - 我相信可以使用CryptptSetKeyParam（https://msdn.microsoft.com/en-us/library/aa380272.aspx）并将KP_MODE设置为CRYPT_MODE_ECB。
答案 1 :(得分：0)
确保您的输入文件不包含任何额外字符，例如新行等.Openssl将在加密时包含这些额外字符。