Question

我试图将教程的澳大利亚计划转换为使用数组。

我输出有问题，即：

% Coloring Australia using nc colors

int: nc = 3;  % number of colors
int: ns = 7;  % number of states
array[1..nc] of string:     colors = ["red", "green", "blue"]; 
array[1..ns] of string:     states = ["wa","nt","sa","q","nsw","v","t"]; 
array[1..ns] of var 1..ns:  indices = [1,2,3,4,5,6,7];

array[1..ns] of var 1..nc: color; % computed color for each state

% I want to use the name as a mnemonic for the index of the state
var int: wa=1; % I know of no alternative to the brute force method
var int: nt=2; var int: sa=3; var int: q=4;
var int: nsw=5; var int: v=6; var int: t=7;

constraint color[wa] != color[nt];  % abutting states
constraint color[wa] != color[sa];
constraint color[nt] != color[sa];
constraint color[nt] != color[q];
constraint color[sa] != color[q];
constraint color[sa] != color[nsw];
constraint color[sa] != color[v];
constraint color[q]  != color[nsw];
constraint color[v]  != color[nsw];

solve satisfy;

/*
  I want a loop to print it out like this:
"wa" = "blue"
"nt" = "green"
...  
*/

output [  
   show( ["\n\(states[j]) = \(colors[color[j]])" | j in indices])
];
/* prints

["\n\"wa\" = \"blue\"", "\n\"nt\" = \"green\"", "\n\"sa\" = \"red\"",     "\n\"q\" = \"blue\"", "\n\"nsw\" = \"green\"", "\n\"v\" = \"blue\"", "\n\"t\" = \"red\""]
*/

如何让show显示\ n新行，而不是转义常量中的引号？像perl双引号而不是单引号？

和/或有没有办法在没有引号的情况下定义常量？像perl qw？

Answer 1

你在代码中犯了一个小错误：show用于输出变量。因此它被用作：

output["this is variable x:" ++ show(x)]

请注意，\(x)是"++show(x)++"

的简写

output语句本身会将给定数组打印为格式化字符串。此格式化的字符串可以包含预期的转义字符。因此，模型的正确输出语句为：

output ["\n\(states[j]) = \(colors[color[j]])" | j in indices];

如何获取MiniZinc输出来解释转义，而不是按字面打印它们？

1 个答案: