Question

我有一个包含字符串的数组，我想解析它来制作每组4个字符串的对象。这可以通过for循环完成吗？

唯一标识组的是每个组将包含4个字符串。

数组看起来像这样，其中顶部值“NumberOfItemsInArray”将是一个数字，表示后面有多少个项目组。项目数量是动态的。

NumberOfItemsInArray
Item1-Name
Item1-Price
Item1-DiscountRate
Item1-Category
Item2-Name
Item2-Price
Item2-DiscountRate
Item2-Category

有没有办法干净利落地做到这一点？

Answer 1

假设你有一些构造函数用于获取4个字符串（a，b，c，d）的YourObject，它应该相当简单，给定输入字符串数组，MyArray和输出List<YourObject> YourObjectList：< / p>

int iItems = System.Convert.ToInt32(MyArray[0]);
for (int i = 0; i < iItems; i+=4)
    YourObjectList.Add( new YourObject( MyArray[i+1], MyArray[i+2], MyArray[i+3], MyArray[i+4] ) );

这应该是正确的 - 虽然通过编译器运行它 - 约翰

Answer 2

根据数组的长度确定四个组的数量。然后只需遍历原始数组，并填充四个数组的数组。

    string[] itemsArray = { "8", "a", "b", "c", "d", "e", "f", "g", "h" };

    int nGroups = (itemsArray.Length - 1) / 4;
    string[][] groups = new string[nGroups][];

    for (int i = 0; i < nGroups; i++) {
        print("- new group of four -"); 
        groups[i] = new string[4];
        for (int j = 0; j < 4; j++) {
            groups[i][j] = itemsArray[i * 4 + j + 1];
            print(groups[i][j]); 
        }
    }

输出：

- new group of four -
a
b
c
d
- new group of four -
e
f
g
h

Answer 3

Array.Lenght看起来很无用，因为你有using System; using System.Collections.Generic; namespace Program { class _Main { // Initialize dictionary with values static Dictionary<string, string> dictionaryWithStrings = new Dictionary<string, string> { { "NumberOfItemsInArray", "2" }, { "Item1-Name", "Some name" }, { "Item1-Price", "0.5$" }, { "Item1-DiscountRate", "?%" }, { "Item1-Category", "Some category" }, { "Item2-Name", "Other name" }, { "Item2-Price", "4$" }, { "Item2-DiscountRate", "24%" }, { "Item2-Category", "Other category" } }; // Create *dynamic* list with Item's static List<Item> objects = new List<Item>(); static void Main() { // "- 1" removes the NumberOfItemsInArray from count // "/ 4" Since you have always 4 strings for (int i = 1; i <= (dictionaryWithStrings.Count - 1) / 4; i++) { objects.Add(new Item { Name = dictionaryWithStrings["Item"+i+"-Name"], Price = dictionaryWithStrings["Item"+i+"-Price"], DiscountRate = dictionaryWithStrings["Item"+i+"-DiscountRate"], Category = dictionaryWithStrings["Item"+i+"-Category"] }); } Console.WriteLine("objects contains [" + objects.Count + "] items, values:"); foreach (Item item in objects) { Console.WriteLine("Item id: [" + objects.IndexOf(item) + "], Name: [" + item.Name + "], Price: [" + item.Price + "], DiscountRate: [" + item.DiscountRate + "], Category: [" +item.Category + "]" ); } } struct Item { public string Name; public string Price; public string DiscountRate; public string Category; } } }，我认为你的数组不是数组，我认为它是字典，如果有的话那么看看这个：

{{1}}

从字符串数组C＃中获取元素组

3 个答案: