Question

我的字符串中包含以下网址：

subdomain.domain.com/ups/a/b.gif
www.domain.com/ups/c/k.gif
subdomain1.domain.com/ups/l/k.docx

想要替换下面的所有网址：

anydomain.com/ups/a/b.gif
anydomain.com/ups/c/k.gif
anydomain.com/ups/l/k.docx

在上面的字符串（URL + ups）中很常见。所有URL都以HTTP或HTTPS启动。

Answer 1

正如评论中所建议的，解析网址的方式是使用parse_url()。

<?php
$urls = [
    "http://subdomain.domain.com/ups/a/b.gif",
    "https://www.example.com/ups/c/k.gif",
    "https://subdomain1.domain.com/ups/l/k.docx",
];
$domain = "anydomain.com";
foreach ($urls as &$url) {
    $u = parse_url($url);
    $url = "$u[scheme]://$domain$u[path]" . (isset($u["query"]) ? "?$u[query]" : "");
}
print_r($urls);

Answer 2

使用：

$new_string = preg_replace("/(http|https):\/\/(?:.*?)\/ups\//i", "$1://anydomain.com/ups/", $old_string);

所以对于输入字符串：

http://subdomain.domain.com/ups/a/b.gif
https://www.domainX.com/ups/c/k.gif
http://subdomain1.domain.com/ups/l/k.docx

输出将是：

http://anydomain.com/ups/a/b.gif
https://anydomain.com/ups/c/k.gif
http://anydomain.com/ups/l/k.docx

Answer 3

您想要使用正则表达式。

解释正则表达式的内容：

# /^(http[s]?:\/\/).*?\/(.*)$/
# 
# / starting delimiter
# ^ match start of string
# (http[s]?:\/\) match http:// or https://
# .*? match all characters until the next matched character
# \/ match a / slash
# (.*) match the rest of the string
# 
# in the replacement
# 
# $1 = https:// or https://
# $2 = path on the url

$urls = [
    'https://subdomain.example.org/ups/a/b.gif',
    'http://www.example.org/ups/c/k.gif',
    'https://subdomain1.example.org/ups/l/k.docx'
];

foreach($urls as $key => $url) {
    $urls[$key] = preg_replace('/^(http[s]?:\/\/).*?\/ups\/(.*)$/', '$1anydomain.com/ups/$2', $url);
}

print_r($urls);

结果

Array
(
    [0] => https://anydomain.com/ups/a/b.gif
    [1] => http://anydomain.com/ups/c/k.gif
    [2] => https://anydomain.com/ups/l/k.docx
)

Answer 4

也许为时已晚... 对于单个字符串：

$components = parse_url( $url);
return str_replace($components['host'], 'anydomain.com', $url);

必须输入网址中的协议。如果网址是数组-循环运行以上

替换域名字符串

4 个答案: