Question

我是Windows表单应用程序的新手我想在文件中保存数据，除了（Sql）或数据库。我尝试了很多东西，我只能在文本文件中存储一个值

TextWriter txt = new System.IO.StreamWriter("E:\\Tahir\\ScaleSystemDataSave\\First.txt");
txt.Write(txtFirsrWeight.Text);
txt.Close();

但我想在文件中存储一个对象我该怎么做呢我的对象是这样的

private void btnSave_Click(object sender, EventArgs e)
{
    FirstTime obj = new FirstTime();
    obj.CardNo = txtCardNo.Text;
    obj.DateTime = txtDateTimePicker.Value;
    obj.VehicleNo = txtVehicalNo.Text;
    obj.WeightType = Convert.ToString(cbxWeigtType.SelectedItem);
    obj.FirstWeight = txtFirsrWeight.Text;
    if (rbtWithDriver.Checked == true)
    {
        obj.IsDriver = (int)Status.WithDriver;
    }
    else if (rbtWithouDriver.Checked == true)
    {
        obj.IsDriver = (int)Status.withOutDriver;
    }

}

Answer 1

您有两种选择。

像逗号分隔文件一样自己格式化文本文件，然后重新读取文件，解析它并将值分配回对象。
使用已知的序列化技术，例如XML或JSON。

以下是实现所需内容的JSON序列化示例。

var first = new FirstTime()
            {
                CardNo = "121515611",
                Date = DateTime.Now.Date,
                VehicleNo = "MNRG23434",
                WeightType = "MyWeight",
                FirstWeight = "FirstWeight"
            };

            var fileText = JsonConvert.SerializeObject(first);

            TextWriter txt = new StreamWriter("C:\\First.txt");
            txt.Write(fileText);
            txt.Close();

            var fileStream = File.Open("C:\\First.txt",FileMode.Open);

            var fileReader = new StreamReader(fileStream);
            var contents = fileReader.ReadToEnd();

            var restoredObject = JsonConvert.DeserializeObject<FirstTime>(contents);

这将按照以下格式存储数据

{"CardNo":"121515611","Date":"2017-03-16T00:00:00+00:00","VehicleNo":"MNRG23434","WeightType":"MyWeight","FirstWeight":"FirstWeight"}

希望对你有所帮助。

除数据库外的数据保存在文件中

1 个答案: