我对我的特定程序有一点怀疑,因为它失败了,我不太清楚为什么,我有一个ExpandableListView对象来执行" Adapter"和一个调用此对象的片段。当显示列表的元素工作时,问题在于onChildClick我想要的是当按下列表中的项目时保存在TextView中并显示它以供稍后使用。由于这是我的程序,它现在只有当我按下另一个元素时才会从列表中选择第一个元素,应用程序停止工作而不会给我一个错误。我该怎么做才能解决这个问题?非常感谢你。
这是ExpandibleList的对象,我在其中调用getChild
$('.slick').slick({
infinite: true,
speed: 5000,
slidesToShow: 1,
centerMode: true,
variableWidth: true,
autoplay: true,
autoplaySpeed: 200,
prevArrow: '',
nextArrow: '',
waitForAnimate: false,
});
这就是我想要从列表中获取项目的地方。
public class ExpandableListAdapter extends BaseExpandableListAdapter {
private Context _context;
private List<String> _listDataHeader ;
private HashMap<String, List<String>> _listDataChild;
public ExpandableListAdapter(Context context, List<String> listDataHeader,
HashMap<String, List<String>> listChildData) {
this._context = context;
this._listDataHeader = listDataHeader;
this._listDataChild = listChildData;
}
@Override
public Object getChild(int groupPosition, int childPosititon) {
return this._listDataChild.get(this._listDataHeader.get(groupPosition))
.get(childPosititon);
}
@Override
public long getChildId(int groupPosition, int childPosition) {
return childPosition;
}
@Override
public View getChildView(int groupPosition, final int childPosition,
boolean isLastChild, View convertView, ViewGroup parent) {
final String childText = (String) getChild(groupPosition, childPosition);
if (convertView == null) {
LayoutInflater infalInflater = (LayoutInflater) this._context
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = infalInflater.inflate(R.layout.list_item, null);
}
TextView txtListChild = (TextView) convertView
.findViewById(R.id.lblListItem);
txtListChild.setText(childText);
return convertView;
}
@Override
public int getChildrenCount(int groupPosition) {
return this._listDataChild.get(this._listDataHeader.get(groupPosition))
.size();
}
@Override
public Object getGroup(int groupPosition) {
return this._listDataHeader.get(groupPosition);
}
@Override
public int getGroupCount() {
return this._listDataHeader.size();
}
@Override
public long getGroupId(int groupPosition) {
return groupPosition;
}
@Override
public View getGroupView(int groupPosition, boolean isExpanded,
View convertView, ViewGroup parent) {
String headerTitle = (String) getGroup(groupPosition);
if (convertView == null) {
LayoutInflater infalInflater = (LayoutInflater) this._context
.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
convertView = infalInflater.inflate(R.layout.list_group, null);
}
TextView lblListHeader = (TextView) convertView
.findViewById(R.id.lblListHeader);
lblListHeader.setTypeface(null, Typeface.BOLD);
lblListHeader.setText(headerTitle);
return convertView;
}
@Override
public boolean hasStableIds() {
return false;
}
@Override
public boolean isChildSelectable(int groupPosition, int childPosition) {
return true;
}
}
如何使用setOnChildClickListener
显示元素答案 0 :(得分:0)
好的,我已经解决了这个问题。我只需要删除 // ShowItem(listDataHeader.get(childPosition));
所以onChildClick看起来像这样:
expListView.setOnChildClickListener(new ExpandableListView.OnChildClickListener() {
@Override
public boolean onChildClick(ExpandableListView parent, View v,
int groupPosition, int childPosition, long id) {
TextName.setText(listAdapter.getChild(groupPosition,childPosition).toString());
return false;
}
});