Question

我正在创建一个表单，您可以从phpmyadmin插入，更新和删除数据库welkom中的数据。这是我的档案Formmenu.php。 PS：此代码包含荷兰语。

PHP

<?php
    if ( ! empty($_POST))
     {
            $mysqli = new mysqli('localhost','root','','welkom');

            if ($mysqli ->connect_error) 
            {
                die('connect error: '. $mysqli->connect_errno . ': ' . $mysqli->connect_error);
            }

                if (isset($_POST['insert'])) {
                     $sql = "INSERT INTO abdijbieren (naam, prijs) VALUES ('{$mysqli->real_escape_string($_POST['naam'])}','{$mysqli->real_escape_string($_POST['prijs'])}');";

                } else if (isset($_POST['delete'])) {
                    $sql = "DELETE FROM abdijbieren WHERE naam ='{$mysqli->real_escape_string($_POST['naam'])}';";
                }
                  else if (isset($_POST['update'])) {
                    $sql = "UPDATE abdijbieren SET id='{$mysqli->real_escape_string($_POST['id'])}' WHERE naam='{$mysqli->real_escape_string($_POST['naam'])}'; UPDATE abdijbieren SET prijs='{$mysqli->real_escape_string($_POST['prijs'])}' WHERE naam='{$mysqli->real_escape_string($_POST['naam'])}';";
                }

                  else {
                      /*nothing*/
                  }



           $insert = $mysqli->query($sql);

            if ($insert)
            {
                echo "Success! Keer terug naar de volgende pagina om te updaten.";
            }else
            {
                die("Error: {$mysqli->errno} : {$mysqli->error}");
            }



            $mysqli->close();
        }

    ?>

表格

<form method="post" action="">
              <input name="naam" type="text" placeholder="naam drank" required><br>
              <input name="prijs" type="text" placeholder="prijs" required><br>
              <input name="id" type="text" placeholder="tracking number*"><br><br>

        <input type="submit" name="insert" value="insert">
        <input type="submit" name="delete" value="delete">
        <input type="submit" name="update" value="update"><br>
        *= niet nodig bij "insert".
        </form>

这是我关注的重点：

$sql = "UPDATE abdijbieren SET id='{$mysqli->real_escape_string($_POST['id'])}' WHERE naam='{$mysqli->real_escape_string($_POST['naam'])}'; UPDATE abdijbieren SET prijs='{$mysqli->real_escape_string($_POST['prijs'])}' WHERE naam='{$mysqli->real_escape_string($_POST['naam'])}';";

当我尝试代码时，我在提交表单后收到错误＃1064。错误回响;

错误：1064：您的SQL语法出错;检查手册对应于您的MariaDB服务器版本以获得正确的语法使用附近＆＃39;更新abdijbieren SET prijs =＆＃39; 5.00 EUR＆＃39; WHERE id =＆＃39; 9＆＃39 ;; 更新一个＆＃39;在第2行

我不确定它是拼写错误还是real_escape_string。我试着寻找一个解决方案：

第二个链接的问题仍然没有解决。我检查了我的代码，看起来很好，但收到错误＃1064后，我对代码感到困惑。我需要帮助解决这个问题。

谢谢。

Answer 1

您可以在一个语句中更新多个列：

$sql = "UPDATE abdijbieren 
           SET id = '" . $mysqli->real_escape_string($_POST['id']) . "',
               prijs = '" . $mysqli->real_escape_string($_POST['prijs']) . "' 
         WHERE naam='" . $mysqli->real_escape_string($_POST['naam']) . "'"

Answer 2

试试这个：

 $sql = "UPDATE abdijbieren SET id='{$mysqli->real_escape_string($_POST['id'])}' , prijs='{$mysqli->real_escape_string($_POST['prijs'])}' WHERE naam='{$mysqli->real_escape_string($_POST['naam'])}'";

Answer 3

无需为每列执行更新查询;你可以通过使用这样的查询来实现这一点：

'update table_name set col_1="col_1_value", col_2 ="col_2_value" where your_condition = abc';

如何在一个查询中创建两个更新语句？

3 个答案: