我有使用WCF的简单客户端应用程序(控制台应用程序)和服务器应用程序(WCF库项目)。我想看看Fiddler中WCF消息的样子。
我将以下代码添加到客户端的app.config:
<configuration>
<system.net>
<defaultProxy>
<proxy bypassonlocal="False" usesystemdefault="True" proxyaddress="http://127.0.0.1:8888" />
</defaultProxy>
</system.net>
我的小提琴手显示来自浏览器的所有连接,除了一个有#34; vshub&#34;在url中,但显示的WCF客户端/服务器应用程序之间没有任何关联。如何配置?
UPDATE1:
我的WCF服务库(服务器应用程序)按以下方式配置:
<system.serviceModel>
<services>
<service name="WcfServer.Service1">
<host>
<baseAddresses>
<add baseAddress = "http://localhost:8733/Design_Time_Addresses/WcfServer/Service1/" />
</baseAddresses>
</host>
<!-- Service Endpoints -->
<!-- Unless fully qualified, address is relative to base address supplied above -->
<endpoint address="" binding="basicHttpBinding" contract="WcfServer.IService1">
<!--
Upon deployment, the following identity element should be removed or replaced to reflect the
identity under which the deployed service runs. If removed, WCF will infer an appropriate identity
automatically.
-->
<identity>
<dns value="localhost"/>
</identity>
</endpoint>
<!-- Metadata Endpoints -->
<!-- The Metadata Exchange endpoint is used by the service to describe itself to clients. -->
<!-- This endpoint does not use a secure binding and should be secured or removed before deployment -->
<endpoint address="mex" binding="mexHttpBinding" contract="IMetadataExchange"/>
</service>
</services>
<behaviors>
<serviceBehaviors>
<behavior>
<!-- To avoid disclosing metadata information,
set the values below to false before deployment -->
<serviceMetadata httpGetEnabled="True" httpsGetEnabled="True"/>
<!-- To receive exception details in faults for debugging purposes,
set the value below to true. Set to false before deployment
to avoid disclosing exception information -->
<serviceDebug includeExceptionDetailInFaults="False" />
</behavior>
</serviceBehaviors>
</behaviors>
</system.serviceModel>
答案 0 :(得分:0)
Fiddler没有抓住本地请求。 Fiddler只捕获实际通过线路的请求。 Windows快捷方式是本地请求。
有an old post有一些替代方案,但我不知道该列表的实际情况。
答案 1 :(得分:0)
您在客户端配置中无需执行任何操作,您可以删除代理设置。如果您不使用“localhost”并将其替换为“MyMachineName”,Fiddler将会工作