在保存json数据时，列数与第1行php的值计数不匹配

Question

我正在尝试读取json数据并将其插入到mysql中， 但是所有列似乎都与值匹配。

以下查询中我错了：

gmrjson.json：

<?php
//First: read data
$fo=fopen("gmrjson.json","r");
$fr=fread($fo,filesize("gmrjson.json"));
$array=json_decode($fr,true);
//Second: create $values
$rows = array();
foreach ($array['rtVisitInfoOpObjV1'] as $key => $value)
$rows[] = "('" . $key . "', '" . $value . "')";
$values = implode(",", $rows); //echo '<pre>';print_r($values);die;


//Save to DB
$hostname = 'localhost';                 
$username = 'root';
$password = '';

try 
{
   $dbh = new PDO("mysql:host=$hostname;dbname=nodejs", $username, $password);
   echo 'Connected to database<br />';
   echo "INSERT INTO gmr(version,visitorId,dwellTime,poiId,srId,zoneId,poiProximi‌​tyConfidence,zonePro‌​ximityConfidence,poi‌​PresenceConfidence,z‌​onePresenceConfidenc‌​e,normalizedTime) VALUES " . $values;
   $count = $dbh->exec("INSERT INTO gmr(version,visitorId,dwellTime,poiId,srId,zoneId,poiProximityConfidence,zoneProximityConfidence,poiPresenceConfidence,zonePresenceConfidence,normalizedTime) VALUES " . $values) or die(print_r($dbh->errorInfo(), true)); 
    echo $count; die;
   $dbh = null;
   echo 'Success<br />';
}
catch(PDOException $e)
{
    echo $e->getMessage();
}
?>

sample.php：

Array
(
[rtVisitInfoOpObjV1] => Array
    (
        [version] => 1
        [visitorId] => vis1
        [dwellTime] => 0
        [poiId] => poi1
        [srId] => sr1
        [zoneId] => zone1
        [poiProximityConfidence] => 0
        [zoneProximityConfidence] => 0
        [poiPresenceConfidence] => 15
        [zonePresenceConfidence] => 0
        [normalizedTime] => 1489574975000
    )

)
Connected to database
INSERT INTO gmr(version,visitorId,dwellTime,poiId,srId,zoneId,poiProximi‌​tyConfidence,zonePro‌​ximityConfidence,poi‌​PresenceConfidence,z‌​onePresenceConfidenc‌​e,normalizedTime) VALUES ('version', '1'),('visitorId', 'vis1'),('dwellTime', '0'),('poiId', 'poi1'),('srId', 'sr1'),('zoneId', 'zone1'),('poiProximityConfidence', '0'),('zoneProximityConfidence', '0'),('poiPresenceConfidence', '15'),('zonePresenceConfidence', '0'),('normalizedTime', '1489574975000')Array
(
[0] => 21S01
[1] => 1136
[2] => Column count doesn't match value count at row 1
)

以下是mysql表的描述

UPDATE-调试生成的查询：

radioButtons[i].Anchor = AnchorStyles.Left;
radioButtons[i].Anchor = AnchorStyles.Bottom;

Answer 1

您可以看到您的SQL错误：

INSERT INTO gmr(version,visitorId,dwellTime,poiId,srId,zoneId,poiProximi‌​tyConfidence,zonePro‌​ximityConfidence,poi‌​PresenceConfidence,z‌​onePresenceConfidenc‌​e,normalizedTime) VALUES ('version', '1'),('visitorId', 'vis1'),('dwellTime', '0'),('poiId', 'poi1'),('srId', 'sr1'),('zoneId', 'zone1'),('poiProximityConfidence', '0'),('zoneProximityConfidence', '0'),('poiPresenceConfidence', '15'),('zonePresenceConfidence', '0'),('normalizedTime', '1489574975000') ...

必须是：

INSERT INTO gmr(version,visitorId,dwellTime,poiId,srId,zoneId,poiProximi‌​tyConfidence,zonePro‌​ximityConfidence,poi‌​PresenceConfidence,z‌​onePresenceConfidenc‌​e,normalizedTime) VALUES (1, 'vis1', '0','poi1','sr1' ...)

你应该删除数字值

周围的单引号

Answer 2

您的查询实际上是提供一对值而不是单个值

而不是这样做：

foreach ($array['rtVisitInfoOpObjV1'] as $key => $value) $rows[] = "('" . $key . "', '" . $value . "')"; $values = implode(",", $rows); //echo '<pre>';print_r($values);die;

这样做

foreach ($array['rtVisitInfoOpObjV1'] as $key => $value) array_push($rows, $value); $values = implode(",", $rows); //echo '<pre>';print_r($values);die;