Question

我有两个Arraylist。 ArrayList workerlist和Arraylist workernamelist

public class Workers {
    private String worker_id;
    private String worker_name;


    public String getWorker_id() {
        return worker_id;
    }

    public void setWorker_id(String worker_id) {
        this.worker_id = worker_id;
    }

    public String getWorker_name() {
        return worker_name;
    }

    public void setWorker_name(String worker_name) {
        this.worker_name = worker_name;
    }


}

Arraylist workernamelist列表包含字符串中的所有工作者名称。我想通过ArrayList workerlist搜索它包含worklist中的wokrername，如果它与worker名称匹配，那么它将返回相应的worker ID。

Answer 1

我认为我们只需要遍历整个worker列表，并且对于每个worker，将它的名称与给定的worker_name进行比较，如果它们相等，则返回worker的id。如果此类worker不存在或worker_name为null，则可以返回null。

public String findWorkerId(ArrayList<Workers> workerList, String workerName) {
    if (workerList == null || workerName == null) {
        return null;
    }
    for (Workers worker : workerList) {
        if (workerName.equals(worker.getWorker_name())) {
            return worker.getWorker_id();
        }
    }
    return null;
}

Answer 2

public Workers searchWorkers(ArrayList workers,String worker_name){
 int len = workers.size();
 for(int i = 0; i<len; i++){
  your logic


    enter code here

 }
}

Answer 3

你需要一个for循环来查看数组列表，然后如果有任何匹配显示匹配或你想做什么。

for(int i =0: i< workernamelist.size(); i++){
   if(workernamelist.worker_ID = worker_ID){
      system.out.println(workerlist.worker_ID);
   }
}

Answer 4

试试这个， public String searchs（ArrayList list_workers，String worker_name）{ for（int i = 0; i＆lt; list_workers.size（）; i ++）{ 如果（list_workers.get（ⅰ）.getWorker_name.equals（WORKER_NAME） { String worker_id = list_workers.get（i）.getWorker_id（）; Log.d（ “TAG”， “worker_id：” + worker_id）; return worker_id; } } return null; }

Answer 5

您可以这样做：

        ArrayList<String> workernamelist=new ArrayList<>();
        ArrayList<Workers> workersArrayList=new ArrayList<>();
        for(int i=0;i<workernamelist.size();i++)
        {
            for(int j=0;j<workersArrayList.size();j++) {
                if (workernamelist.get(i).equalsIgnoreCase(workersArrayList.get(j).getWorker_name()))
                {
                    String id=workersArrayList.get(j).getWorker_id();
                }
            }
        }

比较两种类型的Arraylist和return id

5 个答案: