函数getMyObject（）返回一个名为typedef struct Student{
char firstName[NAME];
char lastName[NAME];
int priority;
int readingLevel;
bookIds* wishlist;
struct Student* next;
}student;
student* buildStudentList(char* studentsFile, student* head)
{
int i;
FILE* fp;
if((fp = fopen(studentsFile, "r")) == NULL)
{
printf("Unable to open file\n");
return 0;
}
student* current = NULL;
char firstName[NAME], lastName[NAME];
int priority, readingLevel;
while(fscanf(fp, "%s %s %d %d",firstName, lastName, &priority, &readingLevel) != EOF)
{
student* tempPtr = malloc(sizeof(student));
tempPtr->next = NULL;
tempPtr->wishlist = NULL;
strcpy(tempPtr->firstName, firstName);
strcpy(tempPtr->lastName, lastName);
tempPtr->priority = priority;
tempPtr->readingLevel = readingLevel;
if(head == NULL)
{
head = tempPtr;
}
else
{
current->next = tempPtr;
}
current = tempPtr;
}
fclose(fp);
return head;
}
的非常长的对象。我只是希望它返回一个非常具体的属性responseObject，其路径为：
mydata我怎样才能通过这条＆＃34;路径＆＃34;到responseObject.data.GetNumber.GetId[1].a.dataset.mydata
以便只返回getMyObject()？该函数应该只返回属性，返回整个对象的选项然后应用＆＃34; path＆＃34;是不可接受的。