我想根据用户角色隐藏/显示模型的某些字段。
实施它的最惯用方法是什么?
我真的不想创建N种不同类型的相同模型(其中N是用户角色的数量)。喜欢: UserEmployee,AdminEmployee,WhateverEmployee。
如果有一些解决方案使用标签,那将是完美的:
type Employee struct {
ID string `visibility:"admin,user"`
Name string `visibility:"admin,user"`
Salary int `visibility:"admin"`
}
jsonBytes, _ := someLib.Marshal(Employee{"1", "John", 5000}, "user")
fmt.Println(string(jsonBytes)) // {"id":"1","name":"John"}
这个问题非常广泛。我只想知道你是如何处理这种情况的,或者在Go社区中最常用的方法是什么。我想要干净和集中(对所有型号都相同)的解决方案,不需要生成大量的重复代码。
我以前尝试过什么:我只是试图为所有情况使用单独的模型并在它们之间进行投射。
答案 0 :(得分:2)
package main
import (
"encoding/json"
"fmt"
"reflect"
"strings"
)
type Employee struct {
ID string `visibility:"admin, hr, user" json:"id,omitempty"`
Name string `visibility:"admin, hr, user" json:"name,omitempty"`
Salary int `visibility:"admin, hr" json:"salary,omitempty"`
Password string `visibility:"admin" json:"password,omitempty"`
Rights map[string]bool `visibility:"admin" json:"rights,omitempty"`
Boss *Employee `visibility:"admin, hr" json:"boss,omitempty"`
}
func filterEmployee(emp Employee, role string) Employee {
var fEmployee Employee
ev := reflect.ValueOf(emp)
et := reflect.TypeOf(emp)
// Iterate through each field within the struct
for i := 0; i < ev.NumField(); i++ {
v := ev.Field(i)
t := et.Field(i)
roles := t.Tag.Get("visibility")
if strings.Contains(roles, role) {
switch i {
case 0: // ID
fEmployee.ID = v.String()
case 1: // Name
fEmployee.Name = v.String()
case 2: // Salary
fEmployee.Salary = int(v.Int())
case 3: // Password
fEmployee.Password = v.String()
case 4: // Rights
fEmployee.Rights = v.Interface().(map[string]bool)
case 5: // Boss
fEmployee.Boss = v.Interface().(*Employee)
}
}
}
return fEmployee
}
func main() {
e := Employee{
"1",
"Jack",
100000,
"password321",
map[string]bool{"create": false, "update": false},
&Employee{
"2",
"John",
120000,
"pwd",
map[string]bool{"create": true, "update": true},
nil,
},
}
fuser := filterEmployee(e, "user")
fhr := filterEmployee(e, "hr")
fadmin := filterEmployee(e, "admin")
buser, err := json.MarshalIndent(fuser, "", " ")
if err != nil {
fmt.Println(err)
}
fmt.Println("Filtering with role user: ")
fmt.Println(string(buser))
bhr, err := json.MarshalIndent(fhr, "", " ")
if err != nil {
fmt.Println(err)
}
fmt.Println("\nFiltering with role hr: ")
fmt.Println(string(bhr))
badmin, err := json.MarshalIndent(fadmin, "", " ")
if err != nil {
fmt.Println(err)
}
fmt.Println("\nFiltering with role admin: ")
fmt.Println(string(badmin))
}
输出:
Filtering with role user:
{
"id": "1",
"name": "Jack"
}
Filtering with role hr:
{
"id": "1",
"name": "Jack",
"salary": 100000,
"boss": {
"id": "2",
"name": "John",
"salary": 120000,
"password": "pwd",
"rights": {
"create": true,
"update": true
}
}
}
Filtering with role admin:
{
"id": "1",
"name": "Jack",
"salary": 100000,
"password": "password321",
"rights": {
"create": false,
"update": false
},
"boss": {
"id": "2",
"name": "John",
"salary": 120000,
"password": "pwd",
"rights": {
"create": true,
"update": true
}
}
}
编辑:更新了提问者请求的答案。
查看以前回答问题的旧游乐场。
答案 1 :(得分:1)
使用“省略空”
type Employee struct {
ID string `json:",omitempty"`
Name string `json:",omitempty"`
Salary int `json:",omitempty"`
}
您的功能可能看起来像
func MarshallEmployee(e Employee, permission string) {
if permission == "user"{
e.Salary = 0
}
....marshall it
}
或者您也可以不首先将值添加到结构中。有关详细信息,请参阅the docs。